Bunuel
A merchant buys 200 kg of rice at $1.25 per kg, 400kg of wheat at $0.75 per kg and 300 kg of tea $0.5 per kg. He sells 100 kg rice at a loss of 25%, 100 kg wheat at a profit of 25% and 100 kg tea a profit of 30%. He then mixes the rest and sells 1/3rd of the mixture at $1 per kg. Approximately at what rate he should sell the remaining mixture, so that he earn a profit of 25% on the whole outlay?
(A) $1.00
(B) $1.06
(C) $1.08
(D) $1.12
(E) $1.15
Rice Total C.P.= \(200*1.25= 250\)
\(100\) kg of rice C.P = \(100*1.25= 125\)
S.P of this \(100\) Kg ( At a loss of \(25\%\)) = \(.75*125= 93.75\)
Wheat Total C.P. = \(400*.75= 300\)
\(100 \)Kg of wheat C.P \(=100*.75= 75\)
S.P of \(100\) Kg of wheat ( at a profit of \(25\%\))= \(1.25*75= 93.75\)
Tea Total C.P. = \(300*.5= 150\)
\(100\) Kg of tea C.P\(= 50\)
S.P of \(100\) Kg ( at a profit of \(30\%\))\(= 1.3*50=65\)
So total quantity sold so far
\(100 +100 +100 = 300\)
Quantity remaining = \(900-300=600\)
\(\frac{1}{3}\) of \(600\) was sold at $1
So \(200\) was sold at $1
Remaining = \(400 \)kg's
Total revenue so far = \(93.75 +93.75+65+ 200= 452.5\)
Trader should make a profit of \(25\%\) on the whole outlay:
Total C.P= \(250+300+150=700\)
At a profit of \(25\% \)means = \(1.25 *700 =875 \)
So total revenue should be \(875\) for a profit of \(25\%\) on the whole outlay.
However so far we have only \(= 452.5 \)
Remaining amount = \(875-452.5= 422.5\)
Also remaining quantity that we have is \(400 \)
Hence remaining quantity should be sold \(\frac{422.5}{400} \approx 1.06 \) per kg for a profit of \(25\%\) on the whole outlay.
Ans-B
Hope it's clear.
(Huff...huff...)