kelleygrad05 wrote:
I actually worked this problem out
I picked numbers for statement 1 and found it to be insufficient where:
N=15, M=5
3n/m = 45/5=15 ---> 15/5=3 -----> n is divisible by m or n/m is an integer
and N=15, M=9
3n/m = 45/9=5 ---> 15/9=1.3333 -----> n is NOT divisible by m or n/m is NOT an integer
For statement 2 I picked numbers:
N=14
13N = 182
M=4 no M=5 no M=6 no
I got lazy at that point and said 182 is an even number and isn't divisible by 4 or 6, probably nothing will work and chose answer E although unsure.
Upon re-examining it, I see 7 would have worked. However I agree if you can express this algebraically as you did and the
OG's answers did, it does become much simpler than picking these vast arrays of numbers.
My problem with your logic (and the
OG's) is that finding statement 2 sufficient is based solely on the fact that 13 is a prime number, is 3 not also a prime? What condition allows you to draw this conclusion for the statement that 13n/m = integer that you can't for 3n/m = integer?
Hi kellygrad05,
For St 2 , we are given that 13N/M= Integer and that 3<M<13<N. Now since M, N are integers, we get Value of M can be from (4,5,6...12) and N can be any no greater than 13.Out of the possible values for M, not a single number can divide 13 because it is prime and its only divisor will be 1 and 13. Then for 13N/M to be an integer N has to be a multiple of M or else 13N/M cannot be an Integer which will contradict the given statement itself.
for St1, we are given that 3N/M =Integer and from Q. stem we get 3<M<13<N. Now In possible values of M that can make 3/M in fraction form will be 6,9 and 12 which will result in 3/M value as 1/2,1/3 and 1/4 respectively.
Now if N=15, and M=3 we get 3N/M =15 as integer and N/M also as Integer(Y).
If N=16 and M=3, we get 3N/M=16 as Integer but N/M is not an Integer(N) and hence not sufficient.
Therefore from St 1 we can get 2 ans and hence not sufficient.
Thanks
Mridul
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