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Departments A, B, and C have 10 employees each, and department D has
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16 Jul 2016, 14:01
3
10
00:00
A
B
C
D
E
Difficulty:
5% (low)
Question Stats:
83% (01:28) correct 17% (02:09) wrong based on 296 sessions
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Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
A. 19,000 B. 40,000 C. 100,000 D. 190,000 E. 400,000
Re: Departments A, B, and C have 10 employees each, and department D has
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16 Jul 2016, 14:49
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Top Contributor
1
Bunuel wrote:
Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
A. 19,000 B. 40,000 C. 100,000 D. 190,000 E. 400,000
Take the task of creating the task force and break it into stages.
Stage 1: Select one person from department A There are 10 people to choose from, so we can complete stage 1 in 10 ways
Stage 2: Select one person from department B There are 10 people to choose from, so we can complete stage 2 in 10 ways
Stage 3: Select one person from department C There are 10 people to choose from, so we can complete stage 3 in 10 ways
Stage 4: Select 2 people from department D Since the order in which we select the 2 people does not matter, we can use combinations. We can select 2 people from 20 people in 20C2 ways (190 ways) So, we can complete stage 4 in 190 ways
By the Fundamental Counting Principle (FCP), we can complete all 4 stages (and thus create a task force) in (10)(10)(10)(190) ways (= 190,000 ways)
Departments A, B, and C have 10 employees each, and department D has
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24 Aug 2018, 11:06
Ratnaa19 the calculation is not too long. As long as you realize that you need to multiply 10*10*10*19*10 = 19*10^4 = 190,000 Moreover, this question is from one of the exam packs.
quick question: I agree with the possibilities for A, B, C (10*10*10). However, I would like to understand why we need to do D with Combinations and we cannot simply say: XY are two employees from department D (20 employees) so we have 20*19= 380 possibilities
update: I can answer myself: actually if you do 20*19, you would count employee XY and YX twice, but it's the same "pair" so that's why we use combinations
Re: Departments A, B, and C have 10 employees each, and department D has
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03 Oct 2019, 11:15
Bunuel wrote:
Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
A. 19,000 B. 40,000 C. 100,000 D. 190,000 E. 400,000
The number of ways to select 1 employee from each of departments A, B, and C and 2 employees from department D is
10C1 x 10C1 x 10C1 x 20C2 = 10 x 10 x 10 x (20 x 19)/2 = 10 x 10 x 10 x 10 x 19 = 190,000
close
83% (01:28) correct 
Moreover, this question is from one of the exam packs.
