Each of the offices in a certain building has a floor area

1) gives us total area, but there are many different ways to add 200, 300 or 350. 2) gives us 10 offices, but we don't know the total area.

If we consider both then we know that 9500 - 10*350= 6000, once again you can have 30 offices with 200 square feet each or 20 offices with 300 square feet each or combination of 200, 300 and 350.

Pretty straightforward.

1) Tells us nothing about the possible breakup of offices. Could be a number of combinations. INSUFFICIENT.
2) Tells us nothing about total office space or total square footage of other office types. INSUFFICIENT.

Taken together we know 10 @ 350 = 3500, so we have 6000 sq feet remaining, but still could be any combo of 200 and 300 sq foot offices.

Is this question as simple as it seems to be or am I missing something?

It's pretty simple, yes.

Each of the offices in a certain building has a floor area of 200, 300, or 350 square feet. How many offices are on the first floor of the building?

(1) There is a total of 9,500 square feet of office space on the first floor of the building. There are many ways to break 9,500 into the sum of 200's, 300's and 350's. Not sufficient.

(2) Ten of the offices on the first floor have floor areas of 350 square feet each. This just tells that there are more than (or equal to) 10 offices on the first floor. Not sufficient.

(1)+(2) 9,500 - 350*10 = 6,000 square feet on the first floor is occupied by 200 or 300 square feet offices. The same here: there are many ways to break 6,000 into the sum of 200's and 300's. Not sufficient.

Answer: E.
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Let's take Statement 2 for instance, when they say stuff like 'Ten of the offices on the first floor have 350 sq feet'
We can assume that they are only describing those 10 and that by no means they are saying that the ONLY ones that have 350 are those ten right?

Cheers
J

Yes, the second statement means that there are exactly ten offices with floor areas of 350 square feet.
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Bunuel EducationAisle I notice that 9500 doesn't completely divide by 200, 300, and 350. So we know that there will be AT LEAST a combination of 2 or 3 of the above sq. feet. to cover the total area of 9500. But how can one come up with 2 - 3 instances (without spending too much time) to see that (1) is insuff.

What I thought was that 300 * 30 gives 9000. If I take one more 300 sq feet I'll get 9300. So 31(300 sq. feet) covers a total of 9300. We are left with 200 sq. feet. So 1(200 sq. feet) can be used to cover the remaining. Hence 1(200) + 31(300) = 9500. So here we have one instance.

Now if I look at 200 sq. feet. 4 * 2 = 8. So if I take 40 (200 sq. feet) I'll get 8000 sq. feet. The remaining 1500 sq. feet can be covered by 5 (300 sq. feet). So 40 (200 sq. feet) + 5 (300 sq. feet.) = 9500 sq. feet. Here we get another instance. Hence (1) is insuff.

BUT, this can take over 30-40 sec. Could you provide a more structured method of approaching this question. As you can see, I just took some random (smart) numbers and saw what is and isn't divisible by 9500.

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