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# f(x) = -5x^197-8x^248+1; f(-1) = ?

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Re: f(x) = -5x^197-8x^248+1; f(-1) = ? [#permalink]
197 is odd number so it will reserve the base sign. 248 is even number so it will change the base sign.

-5(-1) -8(1)+1 = -2

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Re: f(x) = -5x^197-8x^248+1; f(-1) = ? [#permalink]
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f(x)=−5x^197−8x^248+1; f(-1) = ?

f(-1) = -5 (-1)^197 - 8 (-1)^248 +1
= -5 (-1) - 8 (1) +1
= -2

Hence C
A) -16,251
B) -12
C) -2
D) 14
E) 16,251
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f(x) = -5x^197-8x^248+1; f(-1) = ? [#permalink]
$$f(x)=-5x^{197}-8x^{248}+1$$
we have to find value for f(-1)
$$-5(-1)^{197}-8(-1)^{248}+1=5-8+1=-2$$
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Re: f(x) = -5x^197-8x^248+1; f(-1) = ? [#permalink]
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Re: f(x) = -5x^197-8x^248+1; f(-1) = ? [#permalink]
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