Hi,
Here are my two cents for this question
We are told that the average of 5 consecutive number say A,B,C,D,E is odd, which means C is odd . So our Sequence begins with Odd Number , ( O E O E O) this implies A, C ,E are odd and B &D are even
And any Odd number divided by 4 will give remainder as 1 or 3. So we need to know in which for is E is it 4k+1 or 4k+3
Statement 1 tells us that C is prime number , again this means C can be any prime number >2. But again we have E can be any odd number
So Not Sufficient
Statement 2: Tells us that its a square of a integer. from question stem We know that B is even and is square of even number which means B is in the form of 4k.
Since C,D,E are consecutive numbers we have C=4k+1, D=4k+2, E=4k+3
This statement tells us in which form E would be and hence we can answer the question .
Hence Statement 2 is sufficient.
Probus
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Probus
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