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For a recent workday, the graph displays the round-trip distance and m

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Sajjad1994
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For a recent workday, the graph displays the round-trip distance and m [#permalink] New post   Updated on: 04 Feb 2024, 00:59
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For a recent workday, the graph displays the round-trip distance and mode of travel for all persons travelling to work in a medium-sized city.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

1. For all persons who travelled to work by walking, the median round-trip distance (x), in kilometres, satisfies the inequality .

2. For all persons who travelled to work by public transit, the median round-trip distance (x), in kilometres, satisfies the inequality .

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Dropdown 1: x≤2 Dropdown 2: 10<x≤15

Originally posted by Sajjad1994 on 02 Jul 2020, 08:41.
Last edited by BottomJee on 04 Feb 2024, 00:59, edited 10 times in total.
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Re: For a recent workday, the graph displays the round-trip distance and m [#permalink] New post   17 Apr 2021, 04:02
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RO1

The median round-trip distance of the walkers can be found by first determining from the bar graph how many people walked each distance. The results are recorded in the table:


The total number of people walking is 30 + 10 + 6 = 46. Since 46 is an even number, the median distance walked will be the average (arithmetic mean) of the distance walked by the 23rd and 24th walkers, when the distances are listed from least to greatest. Because 30 people walked a distance less than or equal to 2 km, both the 23rd and 24th walkers will be included in this group. Thus, the median is within the distance range d ≤ 2, since the average of two numbers that are less than or equal to 2 will be a number less than or equal to 2.

The correct answer is x ≤ 2.

RO2

Using the method described in the analysis of RO1, the approximate numbers of people traveling each distance by public transit are recorded in the table:


The total number of people taking public transit is 2 + 17 + 30 + 17 +37 = 103. Since 103 is an odd number, the median distance traveled will be that of the middle traveler (the 52nd) when the distances are listed in order. Counting the number of travelers from least to greatest, there are 2 + 17 + 30 = 49 travelers for whom d ≤ 10. Thus, the distance traveled by the 52nd traveler is 10 < d ≤ 15.

The correct answer is 10 < x ≤ 15.


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Re: For a recent workday, the graph displays the round-trip distance and m [#permalink] New post   02 Jul 2020, 22:54
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1. Walking median round trip
=> 30 people walked till distance ≤2
=> 10 people walked till distance 2<X≤5
=> 6 people walked till distance 5<X≤10 = 46 units.

Median = 23&24 value..
Which lies in X≤2

Answer is A

2) Public Transit median round trip
=> 2 people walked till distance ≤2
=> 18 people walked till distance 2<X≤5
=> 30 people walked till distance 5<X≤10
=> 26 people walked till distance 10<X≤15
=> 37 people walked till distance 15<X = 113 units.

Median = 57 value..
Which lies in 10<X≤15

Answer is C

3) For round-trip distances less than or equal to 10 km, the number of persons traveling to work by walking = 30+10+6 = 46 units

For round-trip distances less than or equal to 10 km, the number of persons traveling to work by bicycling = 34+50+40 = 124 units

No. Of people walking is less than bicyclers.

Answer is A

4) For round-trip distances less than or equal to 10 km, the number of persons traveling to work by car = 9+20+28 = 57 units

For round-trip distances less than or equal to 10 km, the number of persons traveling to work by public transit = 2+18+30 = 50 units

No. Of people travelling by car is greater than public transiters.

Answer is C

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Re: For a recent workday, the graph displays the round-trip distance and m [#permalink] New post   03 Jul 2020, 07:36
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1)A,since there are total 47 values in the category of people walking round the trip and the median would be roughly around at the value = 24,which lies in x<=2.

2)C,since people going via public transit in different ranges are:

x<=2 ---2
2<x<=5---18
5<x<=10---30
10<x<=15---26
x>15---37

So here Median = 57,which lies in 10<x<=15

3)A,For round-trip distances <= 10 km, the number of people traveling to work by walking = 30+10+6 = 46 units

For round-trip distances<= 10 km, the number of people traveling to work by bicycling = 34+50+40 = 124 units.No. Of people walking is less than bicycles


4)C,For round-trip distances<= 10 km, the number of people traveling to work by car = 9+20+28 = 57 units

For round-trip distance <=10 km, the number of people traveling to work by public transit = 2+18+30 = 50 units
So,No. Of people travelling by car is greater than public transiters.

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Re: For a recent workday, the graph displays the round-trip distance and m [#permalink] New post   29 Feb 2024, 08:36
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