GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

It is currently 19 Jan 2020, 11:38

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

For any real number x, the operator & is defined as: &(x) = x(1 − x)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 60496
For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 16 Feb 2016, 01:05
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

67% (01:43) correct 33% (01:44) wrong based on 141 sessions

HideShow timer Statistics

Senior Manager
Senior Manager
User avatar
Joined: 20 Aug 2015
Posts: 382
Location: India
GMAT 1: 760 Q50 V44
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 23 Feb 2016, 04:15
Bunuel wrote:
For any real number x, the operator & is defined as:

&(x) = x(1 − x)
If p + 1 = &(p + 1), then p =

A. −1
B. 0
C. 1
D. 2
E. 3


&(x) = x(1 − x)
&(p + 1) = (p + 1)(1 - p - 1) = -p(p+1)

We are given that p + 1 = &(p + 1)
Therefore -p(p+1) = (p + 1)

Or (p + 1) + p(p+1) = 0
(p + 1)^2 = 0
p = -1
Option A
GMAT Club Legend
GMAT Club Legend
User avatar
V
Joined: 12 Sep 2015
Posts: 4214
Location: Canada
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 15 Apr 2018, 07:19
2
Top Contributor
Bunuel wrote:
For any real number x, the operator & is defined as:

&(x) = x(1 − x)
If p + 1 = &(p + 1), then p =

A. −1
B. 0
C. 1
D. 2
E. 3


Let's look at a few examples of this operator (&) in action.
If &(x) = x(1 − x), then...
&(3) = 3(1 − 3) = 3(-2) = -6
&(7) = 7(1 − 7) = 7(-6) = -42
&(-5) = -5(1 − -5) = (-5)(6) = -30
And now.....
&(p+1) = (p+1)[1 − (p+1)] = (p + 1)(-p)

Now onto the question.....
We're told that p + 1 = &(p + 1)
We can now rewrite the right side of the equation as: p + 1 = (p + 1)(-p)
We need to solve this equation for p
Expand the right side to get: p + 1 = -p² - p
Add p² to both sides: p² + p + 1 = -p
Add p to both sides: p² + 2p + 1 = 0
Factor: (p +1)(p +1) = 0
So, p = -1

Answer: A

Cheers,
Brent
_________________
Test confidently with gmatprepnow.com
Image
Non-Human User
User avatar
Joined: 09 Sep 2013
Posts: 13981
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 28 Jun 2019, 13:46
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Bot
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)   [#permalink] 28 Jun 2019, 13:46
Display posts from previous: Sort by

For any real number x, the operator & is defined as: &(x) = x(1 − x)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne