GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 19 Feb 2019, 13:09

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
  • Free GMAT Prep Hour

     February 20, 2019

     February 20, 2019

     08:00 PM EST

     09:00 PM EST

    Strategies and techniques for approaching featured GMAT topics. Wednesday, February 20th at 8 PM EST
  • Online GMAT boot camp for FREE

     February 21, 2019

     February 21, 2019

     10:00 PM PST

     11:00 PM PST

    Kick off your 2019 GMAT prep with a free 7-day boot camp that includes free online lessons, webinars, and a full GMAT course access. Limited for the first 99 registrants! Feb. 21st until the 27th.

For any real number x, the operator & is defined as: &(x) = x(1 − x)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 52971
For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 16 Feb 2016, 00:05
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

72% (01:46) correct 28% (01:54) wrong based on 116 sessions

HideShow timer Statistics

Senior Manager
Senior Manager
User avatar
Joined: 20 Aug 2015
Posts: 388
Location: India
GMAT 1: 760 Q50 V44
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 23 Feb 2016, 03:15
Bunuel wrote:
For any real number x, the operator & is defined as:

&(x) = x(1 − x)
If p + 1 = &(p + 1), then p =

A. −1
B. 0
C. 1
D. 2
E. 3


&(x) = x(1 − x)
&(p + 1) = (p + 1)(1 - p - 1) = -p(p+1)

We are given that p + 1 = &(p + 1)
Therefore -p(p+1) = (p + 1)

Or (p + 1) + p(p+1) = 0
(p + 1)^2 = 0
p = -1
Option A
CEO
CEO
User avatar
D
Joined: 11 Sep 2015
Posts: 3435
Location: Canada
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)  [#permalink]

Show Tags

New post 15 Apr 2018, 06:19
Top Contributor
Bunuel wrote:
For any real number x, the operator & is defined as:

&(x) = x(1 − x)
If p + 1 = &(p + 1), then p =

A. −1
B. 0
C. 1
D. 2
E. 3


Let's look at a few examples of this operator (&) in action.
If &(x) = x(1 − x), then...
&(3) = 3(1 − 3) = 3(-2) = -6
&(7) = 7(1 − 7) = 7(-6) = -42
&(-5) = -5(1 − -5) = (-5)(6) = -30
And now.....
&(p+1) = (p+1)[1 − (p+1)] = (p + 1)(-p)

Now onto the question.....
We're told that p + 1 = &(p + 1)
We can now rewrite the right side of the equation as: p + 1 = (p + 1)(-p)
We need to solve this equation for p
Expand the right side to get: p + 1 = -p² - p
Add p² to both sides: p² + p + 1 = -p
Add p to both sides: p² + 2p + 1 = 0
Factor: (p +1)(p +1) = 0
So, p = -1

Answer: A

Cheers,
Brent
_________________

Test confidently with gmatprepnow.com
Image

GMAT Club Bot
Re: For any real number x, the operator & is defined as: &(x) = x(1 − x)   [#permalink] 15 Apr 2018, 06:19
Display posts from previous: Sort by

For any real number x, the operator & is defined as: &(x) = x(1 − x)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


cron
Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.