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26 Aug 2021, 21:29
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VeritasKarishma
Quote:
When we put r = -20, we get that s must be greater than or equal to -16.25.
If s lies between -5 and 5, we know that s will be greater than -16.25.
Hence there is no conflict among the inequalities.
When we put r = 20, we get s >= 13.75
But s must be between -5 and 5. It cannot be greater than or equal to 13.75.
Hence, r cannot be 20.
17 Sep 2022, 01:19
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KarishmaB
If s is between -5 AND 5, why we are taking "Union" of values for r ( r<-5 and r<8.33) instead of intersection.
I am confused with interpreting the inequality r<=4s+5/3 in terms of min value of r.
Even though s is bounded by min value (-5), r is not bounded by a min value. Why?
Can you explain using graphical representation of inequality for r?
Thank you for your help.
If s is between -5 AND 5, why we are taking "Union" of values for r ( r<-5 and r<8.33) instead of intersection.
I am confused with interpreting the inequality r<=4s+5/3 in terms of min value of r.
Even though s is bounded by min value (-5), r is not bounded by a min value. Why?
Can you explain using graphical representation of inequality for r?
Thank you for your help.
18 Sep 2022, 22:08
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Sneha2021
We are given:
\(r\leq{\frac{(4s + 5)}{3}}\)
For every value of s, we will get a different inequality.
If s = -5, we get r <= -5
If s = -4, we get r <= -11/3
...
If s = 0, we get r <= 5/3
...
If s = 5, we get r <= 25/3
So note that if we take the value of r to be -5 or less than -5, it will satisfy all these inequalities. That is, no matter what the allowed value of s, \(r\leq{\frac{(4s + 5)}{3}}\)
Is there is minimum value r must take? No. It should just not be greater than -5.
Think of it this way: Given a <= -10
What is the minimum value of a here? We don't have a minimum value of a. a could take any value less than -10. It's maximum value is -10.
