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How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat

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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]

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Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8


Any one girl can go with 3 boys.
2nd girl can go with remaining 2 boys
and 3rd girl can go with remaining 1 boy

3! i.e 6 (D) is the answer
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]

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New post 02 Jun 2016, 11:23
First girl can on a date with 3 boys
Second girl can on a date with 2 boys
Third girl can go on a date with 1 boy
Number of possible ways = 3*2*1
=6
Answer D
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]

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Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8


Take the task of arranging dates and break it into stages.

Stage 1: Select a date for Rebecca
There are 3 boys to choose from. So, we can complete stage 1 in 3 ways

Stage 2: Select a date for Kate
There are 2 remaining boys to choose from. So, we can complete stage 2 in 2 ways

Stage 3: Select a date for Ashley
There is 1 remaining boy to choose from. So, we can complete stage 3 in 1 way

By the Fundamental Counting Principle (FCP), we can complete all 3 stages (and thus arrange dates for all 3 women) in (3)(2)(1) ways (= 6 ways)

Answer:
[Reveal] Spoiler:
D


Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. For more information about the FCP, watch this video:


You can also watch a demonstration of the FCP in action here:

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How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]

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Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should not use 3*3?

I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?

Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have

A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2

That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.

So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?

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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]

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New post 18 Aug 2017, 13:54
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genxer123 wrote:
Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should not use 3*3?

I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?

Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have

A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2

That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.

So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?



Someone, please answer this. even I had to read the question two times just to cross-check.
Although this question favors 6 and I completely get it why, but I think a slight word play in question can actually create 9 the right answer.
Would love to see how both the questions look like side by side.

Any experts hear this?
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat   [#permalink] 18 Aug 2017, 13:54
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