Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
Last visit was: 27 Jul 2024, 07:23 |
It is currently 27 Jul 2024, 07:23 |
Customized
for You
Track
Your Progress
Practice
Pays
10:00 AM PDT
-11:00 AM PDT
08:00 AM EDT
-11:59 PM EDT
10:00 AM PDT
-11:00 AM PDT
11:00 AM IST
-01:00 PM IST
05:55 AM PDT
-12:30 PM PDT
10:00 AM EDT
-11:59 PM PDT
Units' Digit of Product of Numbers and Exponents | |
Units' Digit of Power of 2 and 3 | |
Units' Digit of Power of 4 and 5 | |
Units' Digit of Power of 6 and 7 | |
Units' Digit of Power of 8 and 9 | |
We need to find the cycle of units' digit of power of 2 | |
\(2^1\) units’ digit is 2 \(2^2\) units’ digit is 4 \(2^3\) units’ digit is 8 \(2^4\) units’ digit is 6 | \(2^5\) units’ digit is 2 \(2^6\) units’ digit is 4 \(2^7\) units’ digit is 8 \(2^8\) units’ digit is 6 |
We need to find the cycle of units' digit of power of 3 | |
\(3^1\) units’ digit is 3 \(3^2\) units’ digit is 9 \(3^3\) units’ digit is 7 \(3^4\) units’ digit is 1 | \(3^5\) units’ digit is 3 \(3^6\) units’ digit is 9 \(3^7\) units’ digit is 7 \(3^8\) units’ digit is 1 |
We need to find the cycle of units' digit of power of 4 | |
\(4^1\) units’ digit is 4 \(4^2\) units’ digit is 6 | \(4^3\) units’ digit is 4 \(4^4\) units’ digit is 6 |
We need to find the cycle of units' digit of power of 5 | |
\(5^1\) units’ digit is 5 | \(5^2\) units’ digit is 5 |
We need to find the cycle of units' digit of power of 6 | |
\(6^1\) units’ digit is 6 | \(6^2\) units’ digit is 6 |
We need to find the cycle of units' digit of power of 7 | |
\(7^1\) units’ digit is 7 \(7^2\) units’ digit is 9 \(7^3\) units’ digit is 3 \(7^4\) units’ digit is 1 | \(7^5\) units’ digit is 7 \(7^6\) units’ digit is 9 \(7^7\) units’ digit is 3 \(7^8\) units’ digit is 1 |
We need to find the cycle of units' digit of power of 8 | |
\(8^1\) units’ digit is 8 \(8^2\) units’ digit is 4 \(8^3\) units’ digit is 2 \(8^4\) units’ digit is 6 | \(8^5\) units’ digit is 8 \(8^6\) units’ digit is 4 \(8^7\) units’ digit is 2 \(8^8\) units’ digit is 6 |
We need to find the cycle of units' digit of power of 9 | |
\(9^1\) units’ digit is 9 \(9^2\) units’ digit is 1 | \(9^3\) units’ digit is 9 \(9^9\) units’ digit is 1 |
|
Announcements
Tuck at Dartmouth
|