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06 Feb 2012, 03:57
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (00:55) correct
11%
(00:53)
wrong
based on 1670
sessions
History
Date
Time
Result
Not Attempted Yet
If \(0 \leq x \leq 4\) and \(y < 12\), which of the following CANNOT be the value of xy?
A. -2
B. 0
C. 6
D. 24
E. 48
A. -2
B. 0
C. 6
D. 24
E. 48
06 Feb 2012, 04:01
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fiendex
If \(0 \leq x \leq 4\) and \(y < 12\), which of the following CANNOT be the value of xy?
A) -2
B) 0
C) 6
D) 24
E) 48
A) -2
B) 0
C) 6
D) 24
E) 48
The maximum value of x is 4 and the maximum value of y is less than 12 hence xy cannot be 4*12=48, notice that (-4)*(-12)=48 is also impossible as x cannot be less than 0.
Answer: E.
General Discussion
06 Feb 2012, 06:52
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E = 48
48 = XY or -x*-y; as x is not negativ it is would be only possible if xy = 48
AS x<=4 --> y MUST be >=12
Not possible
48 = XY or -x*-y; as x is not negativ it is would be only possible if xy = 48
AS x<=4 --> y MUST be >=12
Not possible
