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lacktutor
a,b — nonzero numbers in the number line.
Is 0 between a and b?
—> a<0 and b>0???

(Statement1):
the distance of 0a > the distance of 0b
—> a= 5, b= 3 —> 5>3 (No)
—> a=—3, b= 2 —> 0a=3, 0b=2 —> 0a> 0b (Yes)
Insufficient

(Statement2):
—> the sum of 0a and 0b > 0(a+b)

If a=3 and b=5, then 0a+0b> 0(a+b)
—> 5+3> 8 —> it does not get an exact match for (stat2)

If a=—3 and b=—5, then 0a+0b> 0(a+b)—> 3+5> 8 ( it is the same thing) if a and b both are negative as you mentioned then 0 is not between them. either a or B has to be -ve and other +ve

If a=—3 and b= 5, then 0a+0b> 0(a+b) —> 3+5> —3+5
8> 2 ( correct)
—> a< 0 and b>0 ( always Yes)
Sufficient

The answer is B

I don't think answer is B for sure, statement 2 is more like |a| + |b| > a+b

Posted from my mobile device
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vanya27
lacktutor
a,b — nonzero numbers in the number line.
Is 0 between a and b?
—> a<0 and b>0???

(Statement1):
the distance of 0a > the distance of 0b
—> a= 5, b= 3 —> 5>3 (No)
—> a=—3, b= 2 —> 0a=3, 0b=2 —> 0a> 0b (Yes)
Insufficient

(Statement2):
—> the sum of 0a and 0b > 0(a+b)

If a=3 and b=5, then 0a+0b> 0(a+b)
—> 5+3> 8 —> it does not get an exact match for (stat2)

If a=—3 and b=—5, then 0a+0b> 0(a+b)—> 3+5> 8 ( it is the same thing) if a and b both are negative as you mentioned then 0 is not between them. either a or B has to be -ve and other +ve

If a=—3 and b= 5, then 0a+0b> 0(a+b) —> 3+5> —3+5
8> 2 ( correct)
—> a< 0 and b>0 ( always Yes)
Sufficient

The answer is B

I don't think answer is B for sure, statement 2 is more like |a| + |b| > a+b

Posted from my mobile device

vanya27

The first two cases in Statement2, both of them do not get an exact match for statement2.
—> If both a and b are positive or negative, 0(zero) will not be between them. Also, you already mentioned it too.

Case3:
Well, In order statement2 to hold true, a should be negative and b should be positive. (a<0, b>0)
—> Is 0(zero) between a and b?— this is what a question is asking.
( Always Yes)
The answer should be B.
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How to solve this using a number line drawing?
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Bunuel
If a and b are nonzero numbers on the number line, is 0 between a and b ?

(1) The distance between 0 and a is greater than the distance between 0 and b.
(2) The sum of the distances between 0 and a and between 0 and b is greater than the distance between 0 and the sum a + b.


I got this wrong but here is the deal.

For sum of distances between ( 0 and a) and (0 and b) to be greater than the distance between (0 and a+b) the 0 has to be in between a and b. If both a and b are on either side of the 0 then the the distances will be equal and not biased.

Hope that makes sense.!
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lacktutor
a,b — nonzero numbers in the number line.
Is 0 between a and b?
—> a<0 and b>0???

(Statement1):
the distance of 0a > the distance of 0b
—> a= 5, b= 3 —> 5>3 (No)
—> a=—3, b= 2 —> 0a=3, 0b=2 —> 0a> 0b (Yes)
Insufficient

(Statement2):
—> the sum of 0a and 0b > 0(a+b)

If a=3 and b=5, then 0a+0b> 0(a+b)
—> 5+3> 8 —> it does not get an exact match for (stat2)

If a=—3 and b=—5, then 0a+0b> 0(a+b)—> 3+5> 8 ( it is the same thing)

If a=—3 and b= 5, then 0a+0b> 0(a+b) —> 3+5> —3+5
8> 2 ( correct)
—> a< 0 and b>0 ( always Yes)
Sufficient

The answer is B

Posted from my mobile device

Great explanatioin lacktutor. One question not quite sure this part of why 5>3 is No? Could you clarify? Thanks

—> a= 5, b= 3 —> 5>3 (No)
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