Bunuel wrote:
If a, b, and c are consecutive positive integers where a < b < c, and c - a = 16/b, then a + b + c =
A. 30
B. 24
C. 18
D. 12
E. 6
PS20355
If a, b, and c are
consecutive positive integers where a < b < c, then we know that:
a + 1 = b
And, more importantly, a + 2 = c
If a + 2 = c, then
c - a = 2GIVEN: c - a = 16/bSubstitute to get:
2 = 16/b
Solve: b =
8So, a, b and c equal 7,
8, and 9 respectively
This means a + b + c = 7 +
8+ 9 = 24
Answer: B
Cheers,
Brent
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Brent Hanneson – Creator of gmatprepnow.com
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