Jul 20 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. Jul 21 07:00 AM PDT  09:00 AM PDT Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes Jul 26 08:00 AM PDT  09:00 AM PDT The Competition Continues  Game of Timers is a teambased competition based on solving GMAT questions to win epic prizes! Starting July 1st, compete to win prep materials while studying for GMAT! Registration is Open! Ends July 26th
Author 
Message 
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 56300

If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
25 Jun 2012, 02:36
Question Stats:
64% (01:46) correct 36% (02:02) wrong based on 2067 sessions
HideShow timer Statistics
If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? (A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 Diagnostic Test Question: 8 Page: 21 Difficulty: 600
Official Answer and Stats are available only to registered users. Register/ Login.
_________________




Math Expert
Joined: 02 Sep 2009
Posts: 56300

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
25 Jun 2012, 02:36
SOLUTIONIf a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 Probably, for most people it would be easier to solve such kind of questions by picking numbers. Notice that January is linked with November and November is linked with December. So, we should pick some smart number for December's revenue. Since the denominators in the question are 5 and 4, the let say December's revenue was 20 (the least common multiple of 4 and 5). So, we have that: Revenue in December = 20; Revenue in November = 20*2/5 = 8; Revenue in January = 8*1/4 = 2; The average of 8 and 2 is 5, so the store's revenue in December was 20/5=4 times that value. Answer: E.
_________________




Current Student
Joined: 29 Mar 2012
Posts: 301
Location: India
GMAT 1: 640 Q50 V26 GMAT 2: 660 Q50 V28 GMAT 3: 730 Q50 V38

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
25 Jun 2012, 04:29
Hi,
Lets say, revenue in November = N was 2/5 of its revenue in December = D revenue in January = J As per given data, N = (2/5)D J = (1/4)N = 1/4 * 2/5 *D = (1/10)D
\(D = \frac {x(N+J)}2\), we need to find x,
\(D = \frac {x((2/5)D+(1/10)D}2\) x = 4,
Thus, Answer is (E).
Regards,



Intern
Joined: 14 Apr 2012
Posts: 13
Location: India
Concentration: Technology, General Management
GMAT Date: 09122012
GPA: 3.5
WE: Information Technology (Retail)

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
26 Jun 2012, 10:11
Use plug in value. Let Dec rev =100 Then Nov rev is 2/5 (100) => 40 Therefore Jan rev = 1/4(Nov rev) = 1/4(40) => 10
Hence Dec rev = x*( Nov rev+Jan rev)/2 100 = x* (40+10)/2 x = 100/25 => 4
Ans) E



Manager
Joined: 02 Jun 2011
Posts: 121

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
26 Jun 2012, 14:09
N = 2/5*D or D = 5/2N J= 1/4*N
avg (N+J) =( N+1/4*N)/ 2 =5/8*N so, avg(N+J)/D = 4
E



Math Expert
Joined: 02 Sep 2009
Posts: 56300

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
29 Jun 2012, 03:05
SOLUTIONIf a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 Probably, for most people it would be easier to solve such kind of questions by picking numbers. Notice that January is linked with November and November is linked with December. So, we should pick some smart number for December's revenue. Since the denominators in the question are 5 and 4, then let say December's revenue was 20 (the least common multiple of 4 and 5). So, we have that: Revenue in December = 20; Revenue in November = 20*2/5 = 8; Revenue in January = 8*1/4 = 2; The average of 8 and 2 is 5, so the store's revenue in December was 20/5=4 times that value. Answer: E.
_________________



Board of Directors
Joined: 01 Sep 2010
Posts: 3421

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
12 Jul 2012, 01:24
600 level. if we translate can write: N= 2/5 D and J = 1/4 N Now observing and substituting we obtaine N = 4J .......ravenues of November and January is 4. E is the answer.
_________________



Veritas Prep GMAT Instructor
Joined: 15 Jul 2015
Posts: 110
GPA: 3.62
WE: Corporate Finance (Consulting)

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
06 Aug 2015, 07:16
Bunuel wrote: If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? (A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 Diagnostic Test Question: 8 Page: 21 Difficulty: 600 If N = 2/5 D and J = 1/4N, we should put all expressions into a common variable. Let's use D. D =D; N =2/5D; and J = 1/10D. Assuming D =10, we now have N = 4 and J = 1. The average of 4 and 1 is 2.5 10 is 4 times greater than 2.5 Answer E is correct
_________________



Intern
Joined: 08 Aug 2015
Posts: 8

If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
20 Nov 2015, 06:19
This can be solved even faster:
The revenue in November (N) is less than half the revenue in December (D). Therefore, December revenue is more than twice the November revenue: \(D>2N\)
The revenue in January (J) is even smaller than revenue in November. Consequently, the average of the two will be less than N: \(Average = (J+N)/2 < N\)
Therefore, December revenue will be far more than twice the average: \(D>2N>2*Average\)
The only option left is (E).



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 14590
Location: United States (CA)

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
29 Nov 2015, 11:50
Hi All, This question can be solved by TESTing VALUES. We're given information comparing revenue for 3 months: 1) November revenue = 2/5 of December revenue 2) January revenue = 1/4 of November revenue We're asked to compare the December revenue to the AVERAGE of November's and January's revenues (and we're asked how many times greater the December revenue is). With the two fractions involved, the common denominator is 20, but you can use any number you like. For example... December revenue = $100 November revenue = (2/5)(100) = $40 January revenue = (1/4)(40) = $10 The average of November and January is (40+10)/2 = 25 Since December revenue is 100, that is 4 TIMES the average of the other two months. Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com*****Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*****
Rich Cohen
CoFounder & GMAT Assassin
Special Offer: Save $75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee www.empowergmat.com/



Director
Status: Professional GMAT Tutor
Affiliations: AB, cum laude, Harvard University (Class of '02)
Joined: 10 Jul 2015
Posts: 696
Location: United States (CA)
Age: 39
GMAT 1: 770 Q47 V48 GMAT 2: 730 Q44 V47 GMAT 3: 750 Q50 V42
WE: Education (Education)

If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
28 Mar 2016, 17:57
Here is a visual that should help. Notice that I simplified the equation using algebra, and then I substituted numbers once the math was simplified. Trying to substitute numbers upfront can also work, but it often involves too much trial and error. Hence the hybrid technique. Please note that "(2d /10)" should have been written as "(2d / 20)."
Attachments
Screen Shot 20160328 at 5.57.03 PM.png [ 128.5 KiB  Viewed 25617 times ]
_________________
Harvard grad and 99% GMAT scorer, offering expert, private GMAT tutoring and coaching worldwide since 2002. One of the only known humans to have taken the GMAT 5 times and scored in the 700s every time (700, 710, 730, 750, 770), including verified section scores of Q50 / V47, as well as personal bests of 8/8 IR (2 times), 6/6 AWA (4 times), 50/51Q and 48/51V. You can download my official testtaker score report (all scores within the last 5 years) directly from the Pearson Vue website: https://tinyurl.com/y7knw7bt Date of Birth: 09 December 1979. GMAT Action Plan and Free EBook  McElroy TutoringContact: mcelroy@post.harvard.edu (I do not respond to PMs on GMAT Club.) ...or find me on Reddit: http://www.reddit.com/r/GMATpreparation



Current Student
Joined: 12 Aug 2015
Posts: 2609

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
25 Dec 2016, 22:35
Nice Official Question. Here is what i did on tis one =>
Method 1> December = x November =2x/5 January =x/10
Mean (J+N)= {2x/5+x/10}/2 => x/4
Hence x=p*x/4 p=4
Hence E
Method 2=> December = 10 November = 4 January => 1
Mean(J+N) = 2.5
Hence 10 = 4 times 2.5
Hence E
_________________



Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 6937
Location: United States (CA)

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
20 Dec 2017, 12:31
Bunuel wrote: If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 We can let n = revenue in November, d = revenue in December, and j = revenue in January. We can create the following equations: n = (2/5)d j = (1/4)n So, j = (1/4)(2/5)d = (1/10)d We now determine that the average revenue for November and January is: [(2/5)d + (1/10)d]/2 [(4/10)d + (1/10)d]/2 (5/10)d/2 = (1/4)d Thus, the revenue in December is d/[(1/4)d] = 4 times the average revenue for November and January. Answer: E
_________________
5star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews If you find one of my posts helpful, please take a moment to click on the "Kudos" button.



Intern
Joined: 11 Aug 2017
Posts: 29
Location: United States
GPA: 3.4

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
04 Jan 2018, 19:00
Kind of tricky... I glanced over the question and found the average for NOV, DEC and JAN instead of just NOV and JAN. I need to read all the way through the problem instead of taking a quick glance. Other than that little issue, the problem isn't difficult at all to solve, if you pick smart numbers.



VP
Joined: 09 Mar 2016
Posts: 1273

If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
17 Apr 2018, 11:39
Bunuel wrote: If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? (A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 Diagnostic Test Question: 8 Page: 21 Difficulty: 600 ok I got it revenue in december 100 revenue in november is 100 November was 2/5 of its revenue in December > N = 2/5*100 = 40 January was 1/4 of its revenue in November > J = 1/4 * 40 = 10 then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? average (arithmetic mean) of its revenues in November and January > \(\frac{40+10}{2}\)\(= 25\) Average revenue 25, hence \(100/25\)\(= 4\) finally !



Manager
Joined: 25 Sep 2018
Posts: 60

If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
09 May 2019, 03:08
Bunuel wrote: If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? (A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4 Diagnostic Test Question: 8 Page: 21 Difficulty: 600 We will calculate L.C.M of the denominators =4*5=20 Let, December revenue =20 November revenue =2/5*20=8 January revenue =1/4*8=2 Now, Average of Nov. & Jan. =8+2/2=5 So, December revenue is 20/5=4 times. Answer is E Posted from my mobile device



Intern
Joined: 05 Nov 2017
Posts: 10

Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
Show Tags
11 May 2019, 21:44
This is purely a reading comprehension question...




Re: If a certain toy store's revenue in November was 2/5 of its
[#permalink]
11 May 2019, 21:44






