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# If k=x/(5^2z^b), where x is a positive integer, and k is expressed as

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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as [#permalink]

Kurtosis wrote:
k will terminate when the denominator of the expression contains only 2's or 5's or both.

What value did you assign to x to get to this conclusion?
Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as [#permalink]
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