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# If k=x/(5^2z^b), where x is a positive integer, and k is expressed as

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Math Expert
Joined: 02 Sep 2009
Posts: 55668
If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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28 Apr 2016, 01:11
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Difficulty:

65% (hard)

Question Stats:

39% (01:16) correct 61% (01:04) wrong based on 55 sessions

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If $$k=\frac{x}{(5^2z^b)}$$, where x is a positive integer, and k is expressed as a decimal, will that decimal terminate?

(1) b = 4
(2) z = 3

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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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28 Apr 2016, 11:41
I think its E

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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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28 Apr 2016, 11:57
1
k will terminate when the denominator of the expression contains only 2's or 5's or both.

St1: b = 4 --> Clearly insufficient as we do not know the value of z

St2: z = 3 --> If z = 3 and b = 0 then the expression may be terminating. If z = 3 and b = 1 then the expression is not terminating.
Not sufficient.

Combining St1 and St2:
k = x/(5^2 * 3^4)
if x = 3^4 then the expression is terminating.
if x = 1 then the expression is non terminating.
Not sufficient

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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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08 Jan 2019, 17:17
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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as   [#permalink] 08 Jan 2019, 17:17
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