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If k=x/(5^2z^b), where x is a positive integer, and k is expressed as

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V
Joined: 02 Sep 2009
Posts: 52296
If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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New post 28 Apr 2016, 00:11
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

44% (01:01) correct 56% (00:54) wrong based on 48 sessions

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Joined: 04 Apr 2015
Posts: 107
Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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New post 28 Apr 2016, 10:41
I think its E

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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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New post 28 Apr 2016, 10:57
1
k will terminate when the denominator of the expression contains only 2's or 5's or both.

St1: b = 4 --> Clearly insufficient as we do not know the value of z

St2: z = 3 --> If z = 3 and b = 0 then the expression may be terminating. If z = 3 and b = 1 then the expression is not terminating.
Not sufficient.

Combining St1 and St2:
k = x/(5^2 * 3^4)
if x = 3^4 then the expression is terminating.
if x = 1 then the expression is non terminating.
Not sufficient

Answer: E
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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as  [#permalink]

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New post 08 Jan 2019, 16:17
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If k=x/(5^2z^b), where x is a positive integer, and k is expressed as &nbs [#permalink] 08 Jan 2019, 16:17
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If k=x/(5^2z^b), where x is a positive integer, and k is expressed as

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