xcusemeplz2009 wrote:
bth the statments are not suff...
s1) let m-0=x, then r-0=3x ( x can be 1,2,3,4,......anything)...not suff
s2) m-12=12-r or r-12=12-m....(can have any value)...not suff
s1)+s2)if m-12=1,2,3,4,5.... then 12-r=3,6,9,12,15...any thing
same for r-12...hence
from bth also we are not getting any particular value
so E
The answer is correct, but there is some problems in solution:
(1) When you write: m=x and r=3x, it's not right: if m=x, then r=3x OR r=-3x, as |r|=3|m|.
(2) You wrote: m-12=12-r or r-12=12-m. If you look at it you'll see that these two equations are the same and derived from \(\frac{m+r}{2}=12\).
Again:
Statement: distance between r and x, is three times the distance between m and x can be expressed as \(|r-x|=3|m-x|\).
Statement: \(k\) is halfway between \(m\) and \(r\) on the number line can be expressed as:
\(\frac{m+r}{2}=k\).
i cud not express it in a correct manner , but my intention was same since i tried on no. line and i got it in a easier way ,however cudn't express that in my post(appologies for that), on a no. line it was clear that the position of m and r is not fix with bth the given information hence insuff....