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# If m is the median of the first 10 positive multiples of 2 and A is th

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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
2
Kudos
no need to calculate mean and median as if we know that it is an A.P then the mean and median will be equal always
so the answer must be 0 which is option C
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2

The first 10 positive multiples of 2 are - $${ 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 }$$

Thus median (m) will be $$\frac{10 + 12}{2}$$ = $$11$$

Average (A) of the first 10 positive multiples of 2 will be = $$11$$

So, A - m = 11 - 11

Thus, answer must be (C) 0
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
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