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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
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no need to calculate mean and median as if we know that it is an A.P then the mean and median will be equal always
so the answer must be 0 which is option C
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2


The first 10 positive multiples of 2 are - \({ 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 }\)

Thus median (m) will be \(\frac{10 + 12}{2}\) = \(11\)

Average (A) of the first 10 positive multiples of 2 will be = \(11\)

So, A - m = 11 - 11

Thus, answer must be (C) 0
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]
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