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If m is the median of the first 10 positive multiples of 2 and A is th

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Joined: 02 Sep 2009
Posts: 49300
If m is the median of the first 10 positive multiples of 2 and A is th  [#permalink]

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31 Jan 2017, 10:19
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92% (00:54) correct 8% (01:50) wrong based on 63 sessions

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If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2

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Joined: 07 Dec 2014
Posts: 1087
Re: If m is the median of the first 10 positive multiples of 2 and A is th  [#permalink]

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31 Jan 2017, 10:55
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2

2+9*2=20
(2+20)/2*10=110
A=110/10=11
m=(10+12)/2=11
A-m=0
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Joined: 25 Apr 2016
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Concentration: Entrepreneurship, Marketing
Re: If m is the median of the first 10 positive multiples of 2 and A is th  [#permalink]

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31 Jan 2017, 23:05
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2

Assuming the series to be 2,4,6,8,.....,20

Sum = 10/2(2*2 + 2(10-1)) = 110 [Using AP formula]
Mean = Sum/n = 110/10 = 11

Median = (10+12)/2 = 11

A-m =0
Senior Manager
Joined: 24 Oct 2016
Posts: 285
Location: India
Concentration: Finance, International Business
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GMAT 1: 550 Q42 V28
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Re: If m is the median of the first 10 positive multiples of 2 and A is th  [#permalink]

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10 Mar 2017, 23:29
1
no need to calculate mean and median as if we know that it is an A.P then the mean and median will be equal always
so the answer must be 0 which is option C
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Re: If m is the median of the first 10 positive multiples of 2 and A is th  [#permalink]

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11 Mar 2017, 00:34
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2

The first 10 positive multiples of 2 are - $${ 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 }$$

Thus median (m) will be $$\frac{10 + 12}{2}$$ = $$11$$

Average (A) of the first 10 positive multiples of 2 will be = $$11$$

So, A - m = 11 - 11

Thus, answer must be (C) 0

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Thanks and Regards

Abhishek....

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Re: If m is the median of the first 10 positive multiples of 2 and A is th &nbs [#permalink] 11 Mar 2017, 00:34
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