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If m is the median of the first 10 positive multiples of 2 and A is th

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If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]

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New post 31 Jan 2017, 10:19
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A
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C
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Question Stats:

92% (00:54) correct 8% (01:50) wrong based on 63 sessions

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If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2

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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]

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New post 31 Jan 2017, 10:55
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2


2+9*2=20
(2+20)/2*10=110
A=110/10=11
m=(10+12)/2=11
A-m=0
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]

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New post 31 Jan 2017, 23:05
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2


Assuming the series to be 2,4,6,8,.....,20

Sum = 10/2(2*2 + 2(10-1)) = 110 [Using AP formula]
Mean = Sum/n = 110/10 = 11

Median = (10+12)/2 = 11

A-m =0
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]

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New post 10 Mar 2017, 23:29
1
no need to calculate mean and median as if we know that it is an A.P then the mean and median will be equal always
so the answer must be 0 which is option C
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Re: If m is the median of the first 10 positive multiples of 2 and A is th [#permalink]

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New post 11 Mar 2017, 00:34
Bunuel wrote:
If m is the median of the first 10 positive multiples of 2 and A is the average (arithmetic mean) of the first 10 positive multiples of 2 what is the value of A – m?

A. 2
B. 1
C. 0
D. –1
E. -2


The first 10 positive multiples of 2 are - \({ 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 }\)

Thus median (m) will be \(\frac{10 + 12}{2}\) = \(11\)

Average (A) of the first 10 positive multiples of 2 will be = \(11\)

So, A - m = 11 - 11

Thus, answer must be (C) 0

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Re: If m is the median of the first 10 positive multiples of 2 and A is th   [#permalink] 11 Mar 2017, 00:34
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If m is the median of the first 10 positive multiples of 2 and A is th

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