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If x ≠ 2 and (8-2(-4+10x))/2-x= 17, what is the value of x?
[#permalink]
13 Dec 2018, 01:05
13 Dec 2018, 01:05
Expert Reply
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Difficulty:
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Question Stats:
92% (01:27) correct
8%
(02:32)
wrong
based on 105
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If \(x \neq 2\) and \(\frac{8-2(-4+10x)}{2-x}= 17\), what is the value of x?
A. -8
B. -6
C. -4
D. -2
E. 0
A. -8
B. -6
C. -4
D. -2
E. 0
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Re: If x ≠ 2 and (8-2(-4+10x))/2-x= 17, what is the value of x?
[#permalink]
13 Dec 2018, 02:49
13 Dec 2018, 02:49
Bunuel wrote:
If \(x \neq 2\) and \(\frac{8-2(-4+10x)}{2-x}= 17\), what is the value of x?
A. -8
B. -6
C. -4
D. -2
E. 0
A. -8
B. -6
C. -4
D. -2
E. 0
solve for x we get
x= -6 IMO B
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Joined: 12 Sep 2015
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Location: Canada
Re: If x ≠ 2 and (8-2(-4+10x))/2-x= 17, what is the value of x?
[#permalink]
23 Mar 2020, 10:02
23 Mar 2020, 10:02
Expert Reply
Top Contributor
Bunuel wrote:
If \(x \neq 2\) and \(\frac{8-2(-4+10x)}{2-x}= 17\), what is the value of x?
A. -8
B. -6
C. -4
D. -2
E. 0
A. -8
B. -6
C. -4
D. -2
E. 0
Given: \(\frac{8-2(-4+10x)}{2-x}= 17\)
Expand the part in the numerator to get: \(\frac{8 + 8 - 20x}{2-x}= 17\)
Simplify the numerator to get: \(\frac{16 - 20x}{2-x}= 17\)
Multiply both sides of the equation by \((2-x)\) to get: \(16 - 20x= 17(2-x)\)
Expand the right side to get: \(16 - 20x= 34-17x\)
Add \(20x\) to both sides to get: \(16= 34+3x\)
Subtract \(34\) from both sides to get: \(-18= 3x\)
Divide both sides by \(3\) to get: \(-6= x\)
Answer: b
Cheers,
Brent
