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BrentGMATPrepNow
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Vyshak
(x + 1)/(x - 1) - 1/3 > 0?

2(x + 3)/3(x -3) > 0? --> We have to find out whether the expression (x + 3)/(x - 3) is positive.

St1: x < 2 --> The expression can be positive, negative or zero.
Insufficient.

St2: x > -1 --> -1 < x < 3 --> Numerator is always positive and denominator is always negative. So the expression is negative.
Sufficient.

Answer: B

I think you may have incorrectly transcribed the question.
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Vyshak
(x + 1)/(x - 1) - 1/3 > 0?

2(x + 3)/3(x -3) > 0? --> We have to find out whether the expression (x + 3)/(x - 3) is positive.

St1: x < 2 --> The expression can be positive, negative or zero.
Insufficient.

St2: x > -1 --> -1 < x < 3 --> Numerator is always positive and denominator is always negative. So the expression is negative.
Sufficient.

Answer: B

I think you may have incorrectly transcribed the question.
Thanks. I have corrected it now. But the steps seem to be fine.
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Step 1-
(x-3)+4
X-3
gives
1+4/(x-3)>1/3
(2/(x-3))>-1/3
Now, option b , since x>-1 & <3,LHS can never be greater than -1/3
So B is sufficient
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GMATPrepNow
If x < 3, is \(\frac{x + 1}{x - 3}\) > 1/3?

(1) x < 2

(2) x > -1

\(\frac{x+1}{x-3}>1/3…\frac{(x+1)3-(x-3)1}{3(x-3)}>0…\frac{3x+3-x+3}{3x-9}>0…\frac{2(x+3)}{3(x-3)}>0\)
\(\frac{2(x+3)}{3(x-3)}>0…\frac{(x+3)}{x-3}>0…true:x<-3\)
\((ie).x=-7:\frac{2(-7+3)}{3(-7-3)}>0…\frac{2(-4)}{3(-10)}>0…\frac{-8}{-30}>0\)

(1) x < 2 insufic

(2) x > -1 sufic

Ans (B)
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