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If x and y are two points on the number line what is the value of x + y?
(1) 6 is halfway between x and y
(2) y = 2x
(1) 6 is halfway between x and y
(2) y = 2x
24 Oct 2009, 09:44
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I have to disagree with C. The answer to the question must be A.
If x and y are two points on the number line what is the value of x + y?
(1) 6 is halfway between x and y. On the GMAT we often see such statement and it can ALWAYS be expressed algebraically as \(6=\frac{x+y}{2}\) --> \(x+y=12\). Remember we are asked to determine the value of \(x+y\) not \(x\) and \(y\). Sufficient.
(2) y=2x. Clearly not sufficient
Answer: A.
Hope it's clear.
If x and y are two points on the number line what is the value of x + y?
(1) 6 is halfway between x and y. On the GMAT we often see such statement and it can ALWAYS be expressed algebraically as \(6=\frac{x+y}{2}\) --> \(x+y=12\). Remember we are asked to determine the value of \(x+y\) not \(x\) and \(y\). Sufficient.
(2) y=2x. Clearly not sufficient
Answer: A.
Hope it's clear.
General Discussion
24 Oct 2009, 05:04
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IMO C.
stmt 1: x and y can be anything...(4,8) (5,7)....(-12,24).
stmt 2: y = 2x, again we can have (4,8) (5,10)...since 6 is not necessarily the midpoint of the line segment under consideration.
combining, 6+c = y = 2x, 6-c=x
adding these two equations, we get 12 = 3x => x = 4, y=8. This is the only possibility that satisfies both conditions.
However, if stmt 2 was something like: |y| = |2x|, then answer would have been E.
stmt 1: x and y can be anything...(4,8) (5,7)....(-12,24).
stmt 2: y = 2x, again we can have (4,8) (5,10)...since 6 is not necessarily the midpoint of the line segment under consideration.
combining, 6+c = y = 2x, 6-c=x
adding these two equations, we get 12 = 3x => x = 4, y=8. This is the only possibility that satisfies both conditions.
However, if stmt 2 was something like: |y| = |2x|, then answer would have been E.
