Bunuel
If x is a positive integer and \(x^y = 1\), what is the value of x?
(1) \(y^x = 2\)
(2) y is a positive integer
Given: x is a positive integer and \(x^y = 1\) From the given information, there are exactly two possible cases:
case i: x = 1 and y = any value
case ii: x = any positive integer and y = 0Target question: What is the value of x? Statement 1: \(y^x = 2\) This rules out
case ii (since \(0^x=0\)), which means
case i must be true
If
case i is true, then
x = 1Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: y is a positive integerThis rules out
case ii (since 0 is not a positive integer), which means
case i must be true
If
case i is true, then
x = 1Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: D
Cheers,
Brent