BrentGMATPrepNow wrote:
If 2x² + y³ + 3x – 2y + xy + 1 is even, is x + y odd?
(1) xy is even
(2) y is even
Answer:
Target question: Is x + y odd? Given: 2x² + y³ + 3x – 2y + xy + 1 is even STRATEGY: When the given information in a data sufficiency question yields a limited number of possible cases (5 or fewer), you can save make things easier by listing those possible cases before analyzing each statement.
For the given information, we need only test 4 possible cases (i.e., x and y are both even, x is even and y is odd, etc.)
To test each case, I like to plug in 0 for even numbers and 1 for odd numbers.
When I do this, I get:
So, there are exactly 3 cases in which 2x² + y³ + 3x – 2y + xy + 1 is even.
I'm now ready for the statements!!! Statement 1: xy is even xy is even in cases i and ii
Since the answer to the target question (
Is x + y odd?) is
YES for cases i and ii, it MUST be the case that
x + y is oddSo, statement 1 is SUFFICIENT
Statement 2: y is eveny is even in only one of the three possible cases (case ii), which means it MUST be the case that
x + y is oddSo, statement 2 is SUFFICIENT
Answer: D