|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
84% (02:27) correct
16%
(02:54)
wrong
based on 1333
sessions
History
Date
Time
Result
Not Attempted Yet
In a survey of 248 people, 156 are married, 70 are self-employed and 25% of those who are married are self-employed. If a person is to be randomly selected from those surveyed, what is the probability that the person selected will be self-employed but not married?
A. 1/8
B. 4/31
C. 117/248
D. 1/4
E. 31/117
A. 1/8
B. 4/31
C. 117/248
D. 1/4
E. 31/117
Every tricky question should trigger a follow up quiz.
Build that habit with
GMAT Club Forum Quiz →.
whiplash2411
Joined: 09 Jun 2010
Last visit: 02 Mar 2015
Posts: 1,761
Given Kudos: 210
Status:Three Down.
Concentration: General Management, Nonprofit
Schools: HBS '17 (M) Stanford '17 (A)
14 Jun 2010, 06:54
Kudos
Bookmarks
I am not sure if my method is correct, but here's how I think you should approach this problem:
Total number of people = 248
Number of married people = 156
Number of self employed people = 70
Number of people who are married AND self employed = 25% of 156 = 39
Number of people who are self employed but not married = People self employed - People self employed/married
Thus, number of people who are self employed but not married = 70-39 = 31
Thus probability = 31/248 = 1/8
Does this match the correct answer specified?
Also, I've attached a diagrammatic view of how this might work.
@Others: Please let me know if my approach is right!
Total number of people = 248
Number of married people = 156
Number of self employed people = 70
Number of people who are married AND self employed = 25% of 156 = 39
Number of people who are self employed but not married = People self employed - People self employed/married
Thus, number of people who are self employed but not married = 70-39 = 31
Thus probability = 31/248 = 1/8
Does this match the correct answer specified?
Also, I've attached a diagrammatic view of how this might work.
@Others: Please let me know if my approach is right!
Attachments
File comment: Venn Diagram Version of Problem
ProbI.JPG [ 18.3 KiB | Viewed 19389 times ]
14 Jun 2010, 06:59
Kudos
Bookmarks
I would put the figures into a table:
[tried to post link to my table - but due to the fact that i dont have enough posts/not long enough member of this forum can't post the link - pm me if you need it.
(Table columns: married, not-married, total
table rows: self-employed, not self-employed & total)
Than you can start to plug in the given values (Total surveyed: 248, total married: 156, total self-employed:70)
Now calculate 25% of 156 (share of self-employed & married)
And you end up with 39. It's quite easy to define all other values - but not needed for the anwer:
39/248=1/8
[tried to post link to my table - but due to the fact that i dont have enough posts/not long enough member of this forum can't post the link - pm me if you need it.
(Table columns: married, not-married, total
table rows: self-employed, not self-employed & total)
Than you can start to plug in the given values (Total surveyed: 248, total married: 156, total self-employed:70)
Now calculate 25% of 156 (share of self-employed & married)
And you end up with 39. It's quite easy to define all other values - but not needed for the anwer:
39/248=1/8
