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D 18

just put values and compare with the 3 digit number.
calculating 18, gives us 198 as total and numbers of 11+88+99 which indeed equals 198

==17==187 ===11+77+88 not equal 187
===19==209=22+00+99 not equal 209
==15===165==11+66+55 not equal 165
===12==132 ==11+22+33 is even less than 100
==18===198== 11+99+88 is exactly 198. Bingo
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AA + BB + CC = ABC

From above, A+B+C = 10 + C => A+B = 10
Again, A+B+C+1 = 10A + B => 9A = C+1

Since, A+B is equal to 10, if A=0, then B=10. So A!=0. => A=1 and C=8. Single digit integers.
=> B = 9.

So the numbers are 11, 99, 88 and sum of the digits is 18.
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Bunuel
AA
+
BB
+
CC
___
ABC

In the correctly worked addition problem above, A, B, and C are distinct digits. What is the sum of A, B and C ?

A. 12
B. 15
C. 17
D. 18
E. 19



Are You Up For the Challenge: 700 Level Questions
People have committed to brute force however we can simply and check whether we can come to the right conclusion

10(A+B+C) +A+B+C=100(A)+10B +C
=>10(A+C) +A+B =100A......
WHICH WE GET IF WE SUBSTITUTE the values a=1 b=9 and c=8

Therefore IMO D
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MartyMurray KarishmaB Can you please provide your solution for this question ?
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Hello from the GMAT Club BumpBot!

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