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In the figure above, is AB > BC? (Note: Figure not necessarily drawn

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In the figure above, is AB > BC? (Note: Figure not necessarily drawn  [#permalink]

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New post 23 Aug 2016, 02:44
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

78% (01:44) correct 22% (02:16) wrong based on 107 sessions

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Re: In the figure above, is AB > BC? (Note: Figure not necessarily drawn  [#permalink]

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New post 23 Aug 2016, 05:01
Bunuel wrote:
Image
In the figure above, is AB > BC? (Note: Figure not necessarily drawn to scale.)

(1) AB > CD
(2) (AD − AB) > (AD − BC)

Attachment:
2016-08-23_1343.png


Need to find AB > BC.

Stat 1: We are not sure of the individual lengths of AB and CD to confirm on this equation...Insufficient.

Stat 2: (AD − AB) > (AD − BC) => BC - AB > 0 .. BC > AB ..Sufficient to answer...

IMO option B is correct answer..
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Re: In the figure above, is AB > BC? (Note: Figure not necessarily drawn  [#permalink]

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New post 23 Aug 2016, 08:15
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Bunuel wrote:
Image
In the figure above, is AB > BC? (Note: Figure not necessarily drawn to scale.)

(1) AB > CD
(2) (AD − AB) > (AD − BC)

Attachment:
2016-08-23_1343.png


Target question: Is AB > BC?

Statement 1: AB > CD
This statement doesn't FEEL sufficient, so I'll TEST some values.
There are several scenarios that satisfy statement 1. Here are two:
Case a: AB = 3, BC = 1, and CD = 1. In this case, AB > BC
Case b: AB = 3, BC = 4, and CD = 1. In this case, AB < BC
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Aside: For more on this idea of plugging in values when a statement doesn't feel sufficient, you can read my article: http://www.gmatprepnow.com/articles/dat ... lug-values

Statement 2: (AD − AB) > (AD − BC)
Take AD − AB > AD − BC
Subtract AD from both sides to get: -AB > -BC
Multiply both sides by -1 to get: AB < BC
PERFECT!!
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Aside: notice that when we multiplies both sides by -1, we REVERSED the direction of the inequality symbol.

Answer =

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Re: In the figure above, is AB > BC? (Note: Figure not necessarily drawn  [#permalink]

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New post 07 Feb 2019, 00:35
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Re: In the figure above, is AB > BC? (Note: Figure not necessarily drawn   [#permalink] 07 Feb 2019, 00:35
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