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Sub 505 Level|   Algebra|            
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gmatt1476
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In the formula shown, if g is a constant and x = –6 when t = 2, what i 27 Apr 2020, 13:24
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A
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\(x = \frac{1}{6}gt^2\)
In the formula shown, if g is a constant and x = –6 when t = 2, what is the value of x when t = 4 ?

A. –24
B. –20
C. –15
D.  20
E.  24


PS89821.02
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A
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In the formula shown, if g is a constant and x = –6 when t = 2, what i 27 Apr 2020, 13:29
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\(x = \frac{1}{6}gt^2\)

\(\frac{x_1}{x_2} = \frac{t_1^2}{t_2^2}\)

\(\frac{-6}{x_2 }= \frac{2^2}{4^2}\)

\(x_2 = -24\)


Bunuel
\(x = \frac{1}{6}gt^2\)
In the formula shown, if g is a constant and x = –6 when t = 2, what is the value of x when t = 4 ?

A. –24
B. –20
C. –15
D.  20
E.  24


PS89821.02
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In the formula shown, if g is a constant and x = –6 when t = 2, what i 27 Apr 2020, 17:14
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gmatt1476
\(x = \frac{1}{6}gt^2\)
In the formula shown, if g is a constant and x = –6 when t = 2, what is the value of x when t = 4 ?

A. –24
B. –20
C. –15
D.  20
E.  24


PS89821.02
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Given: \(x = \frac{1}{6}gt^2\)

Also given: When \(t = 2\), \(x = -6\)
Plug these values into our given equation to get: \(-6 = \frac{1}{6}(g)(2^2)\)

Simplify: \(-6 = \frac{1}{6}(g)(4)\)

Simplify: \(-6 = \frac{4g}{6}\)

Multiply both sides of the equation by \(6\) to get: \(-36 = 4g\)

Solve: \(g = -9\)

So the original equation becomes: \(x = \frac{1}{6}(-9)t^2\)

What is the value of x when t = 4 ?
We get: \(x = \frac{1}{6}(9)(4^2)= \frac{1}{6}(-9)(16) = -24\)

Answer: A

Cheers,
Brent
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In the formula shown, if g is a constant and x = –6 when t = 2, what i 21 Dec 2020, 05:21
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gmatt1476
\(x = \frac{1}{6}gt^2\)
In the formula shown, if g is a constant and x = –6 when t = 2, what is the value of x when t = 4 ?

A. –24
B. –20
C. –15
D.  20
E.  24
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We need to get the constant (g) first; \(x = \frac{1}{6}gt^2\); \(-6 = \frac{1}{6}g2^2\) \(= -6 = \frac{1}{6}4g\); \(g=-9\)

Now putting \(g=-9\) in the original equation;\(x = \frac{1}{6}gt^2\)=\(x = \frac{1}{6}-9*4^2\)

\(=x = \frac{1}{6}-9*16\)

\(x=-24\)

The answer is \(A\)
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In the formula shown, if g is a constant and x = –6 when t = 2, what i 21 Dec 2020, 08:27
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x = \(\frac{1}{6} * g * t^2\)

=> g = \(\frac{(6x) }{ t^2}\)

=> g = \(\frac{(6 * -6) }{ (2^2)} = \frac{-36}{4} = -9\)

At t = 4:

=> x = \(\frac{1}{6} * (-9) * (4^2)\)

=> x = -24

Answer A
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In the formula shown, if g is a constant and x = –6 when t = 2, what i 10 Feb 2025, 19:16
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