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Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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02 Jul 2012, 21:25
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Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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02 Jul 2012, 21:38
Hi,
Using (1), xy=6 x=3, y=3 then, x=y but when x=9, y=3 \(x \neq y\). Insufficient.
Using (2), x+y=0 or x = y, when y=1, x=1 and x=y, Sufficient.
Thus, Answer (B)
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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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02 Jul 2012, 23:38



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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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16 May 2013, 09:34
catennacio wrote: Is │x│=│y│?
(1) x  y = 6 (2) x + y = 0 x= y + 6 stmt1 x= y > !x! = !y! so stmt1 is the answer B is the choice



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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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12 Jun 2013, 12:07
My first instinct was to manipulate x=y
x=y OR x=y
1.) says that xy=6 which means we can get values for x and y
x=6+y y=x6
So, for x=y
6+y=y 6=0 (Invalid)
x=x6 0=6 (Invalid)
So, for x=y
6+y=y y=3
x=x+6 x=3
Why wouldn't we use that methodology on this problem?



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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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12 Jun 2013, 12:27
WholeLottaLove wrote: My first instinct was to manipulate x=y
x=y OR x=y
1.) says that xy=6 which means we can get values for x and y
x=6+y y=x6
So, for x=y
6+y=y 6=0 (Invalid)
x=x6 0=6 (Invalid)
So, for x=y
6+y=y y=3
x=x+6 x=3
Why wouldn't we use that methodology on this problem? Are you saying that A is sufficient? In the case \(x=3\) and \(y=3\) => \(x=y\). But if \(x=90\) and \(y=84\) then x  y = 6 but \(x\neq{y}\). The question asks you if x=y OR x=y, you cannot assume that it's true in your solution to find the values of x,y for which it holds ture.
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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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12 Jun 2013, 12:43
I should have worded that better. I guess that solving the problem they way I did, I would say A is correct. I see that for xy=6 there could be many values for x and y, however, it seems like many similar problems are solved by manipulating statements (i.e. xy=6) and plugging into x=y or x=y. I understand how this problem was solved, but I want to understand WHY it was solved the way it was. As always, thank you for for help. Zarrolou wrote: WholeLottaLove wrote: My first instinct was to manipulate x=y
x=y OR x=y
1.) says that xy=6 which means we can get values for x and y
x=6+y y=x6
So, for x=y
6+y=y 6=0 (Invalid)
x=x6 0=6 (Invalid)
So, for x=y
6+y=y y=3
x=x+6 x=3
Why wouldn't we use that methodology on this problem? Are you saying that A is sufficient? In the case \(x=3\) and \(y=3\) => \(x=y\). But if \(x=90\) and \(y=84\) then x  y = 6 but \(x\neq{y}\). The question asks you if x=y OR x=y, you cannot assume that it's true in your solution to find the values of x,y for which it holds ture.



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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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12 Jun 2013, 12:48
WholeLottaLove wrote: My first instinct was to manipulate x=y
x=y OR x=y
1.) says that xy=6 which means we can get values for x and y
x=6+y y=x6
So, for x=y
6+y=y 6=0 (Invalid)
x=x6 0=6 (Invalid)
So, for x=y
6+y=y y=3
x=x+6 x=3
Why wouldn't we use that methodology on this problem? When you assume that x=y and solve the equation [xy = 6], you WILL get invalid solutions as you got because you have anyways assumed that x=y> xy = 0;which contradicts the given fact. However, when you assume that x=y>x+y=0, you have inherently assumed that x IS equal to y and now you are just solving for the values of x and y. Thus, the equation [xy=6] would really not make any difference for this method.( xy) could equal anything and you would still get x = y.
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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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12 Jun 2013, 12:52
Ahhh! That makes sense! I am assuming x = y when I am trying to verify if it does or does not. Thanks! vinaymimani wrote: WholeLottaLove wrote: My first instinct was to manipulate x=y
x=y OR x=y
1.) says that xy=6 which means we can get values for x and y
x=6+y y=x6
So, for x=y
6+y=y 6=0 (Invalid)
x=x6 0=6 (Invalid)
So, for x=y
6+y=y y=3
x=x+6 x=3
Why wouldn't we use that methodology on this problem? When you assume that x=y and solve the equation [xy = 6], you WILL get invalid solutions as you got because you have anyways assumed that x=y> xy = 0;which contradicts the given fact. However, when you assume that x=y>x+y=0, you have inherently assumed that x IS equal to y and now you are just solving for the values of x and y. Thus, the equation [xy=6] would really not make any difference for this method.( xy) could equal anything and you would still get x = y.



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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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12 Jun 2013, 12:53
Yes Wotta you should manipolate the statement to understand the question better. Is \(x=y\)? it s like saying is x=y or x=y? But once you start analyzing the statement you cannot use that info.
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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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01 Oct 2016, 20:22
Look into the question as  we need to find out if the numeric value of A and B are equal or not. Statement1: Case 1 A=12 B=6 AB=6 or A=3 and B=3 AB=6 NOT SUFFICIENT
Statement2: A+B=0 This condition is only possible when both A and B are of same numeric values however their signs are opposite or A and B are both 0. In both the case Mod A= Mod B
Hope this helps



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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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24 Feb 2017, 03:55
Prompt analysis x and y are real numbers Superset The answer to this question will be either yes or no. Translation In order to find the answer, we need: 1# exact value of x and y. 2# 2 equation in x and y to find their exact value 3# any other specific equation or properties to determine if the condition holds true. Statement analysis St 1: xy = 6. We take two values for (x,y) i.e. (4,2) and (3,3)for former it doesn't hold true and for latter it holds true. INSUFFICIENT St 2: x +y = 0 or x = y. Taking mod on both side we can say that x = y. Answer Option B
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Re: Is │x│=│y│? (1) x  y = 6 (2) x + y = 0
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