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Re: Is z less than 0? (1) xy > 0 and yz < 0. (2) x > 0 [#permalink]
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Is z less than 0?

Statement 1: xy > 0 and yz < 0.

xy > 0 means x and y have the same sign. i.e. if x>0 then y>0 and if x<0 then y<0

also, yz<0 means y and z have the opp. sign. Now since y can be either greater than 0 or less than zero, hence z can also attain two different value greater than zero when y is less than zero and less than zero when y is greater than zero.

Hence not sufficient

Statement 2 x > 0

this doesn't tell us anything about z hence not sufficient

combining statement 1 and 2 we know that both x and y are greater than zero. hence z will be less than zero. Thus sufficient.

hence C
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Re: Is z less than 0? (1) xy > 0 and yz < 0. (2) x > 0 [#permalink]
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Step 1: Analyse Question Stem
We have to calculate if z is less than zero.

Step 2: Analyse Statements Independently (And eliminate options) – AD / BCE


Statement 1: xy > 0 and yz < 0.

The product of x and y is greater than zero; this means that x and y have the same signs.
The product of y and z is lesser than zero; this means that y and z have opposite signs.

Therefore, x and z are also of opposite signs.
However, since we do not know the exact signs of x and y, the sign of z cannot be calculated.

The data in statement 1 is insufficient to find out if z is less than zero.
Statement 1 alone is insufficient. Answer options A and D can be eliminated.

Statement 2: x > 0

Knowing that x is a positive value is not sufficient to find whether z is negative or not.
The data in statement 2 is insufficient to find out if z is less than zero.
Statement 2 alone is insufficient. Answer option B can be eliminated.


Step 3: Analyse Statements by combining


From statement 1: x and z are of opposite signs
From statement 2: x > 0
Therefore, z < 0.

The combination of statements is sufficient to answer that z is lesser than zero.
Statements 1 and 2 together are sufficient. Answer option E can be eliminated.

The correct answer option is C.
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Re: Is z less than 0? (1) xy > 0 and yz < 0. (2) x > 0 [#permalink]
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Re: Is z less than 0? (1) xy > 0 and yz < 0. (2) x > 0 [#permalink]
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