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02 Mar 2018, 01:21
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[GMAT math practice question]
John traveled the entire 50 km trip. If he traveled the first 20 km of the trip at a constant rate 40 km per hour and the remaining trip at a constant rate 20 km per hour, what is his average speed, in km per hour?
A. 20 km/h
B. 23 km/h
C. 25 km/h
D. 26 km/h
E. 27 km/h
John traveled the entire 50 km trip. If he traveled the first 20 km of the trip at a constant rate 40 km per hour and the remaining trip at a constant rate 20 km per hour, what is his average speed, in km per hour?
A. 20 km/h
B. 23 km/h
C. 25 km/h
D. 26 km/h
E. 27 km/h
02 Mar 2018, 02:00
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MathRevolution
If John travels 20 km at 40 km/hr he would take \(\frac{1}{2}\) hour.
The remainder of the trip - 30 km was traveled at 20 km/hr and took a time of \(\frac{30}{20} = \frac{3}{2}\) hours.
The total time taken is 2 hours and the distance traveled is 50 km.
Therefore, the average speed at which John travels is \(\frac{50}{2} = 25\)km/h (Option C)
02 Mar 2018, 07:33
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MathRevolution
Average speed = total distance/total travel time
total distance = 50 km
total travel time = time spent driving at 40 kmh + time spent driving at 20 kmh
time = distance/speed
So, time spent driving at 40 kmh = 20/40 = 1/2 hour
And time spent driving at 20 kmh = 30/20 = 3/2 hours
So, TOTAL travel time = 1/2 + 3/2 = 4/2 = 2 hours
Average speed = 50/2 = 25 kmh
Answer: C
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