It is currently 14 Dec 2017, 16:50

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

M02-32

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

M02-32 [#permalink]

Show Tags

New post 15 Sep 2014, 23:18
Expert's post
6
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

63% (00:40) correct 37% (00:39) wrong based on 219 sessions

HideShow timer Statistics

Kudos [?]: 135661 [0], given: 12705

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

Re M02-32 [#permalink]

Show Tags

New post 15 Sep 2014, 23:18
Official Solution:


Statement (1) by itself is sufficient. From Statement (1):
\(x^2 = 2x - 1\)
\(x^2 - 2x + 1 = 0\)
\((x-1)^2 = 0\)
\(x -1 = 0\)
\(x = 1\)

Thus, \(x^2 = 1\).

Statement (2) by itself is insufficient. From Statement (2):
\(x^2 - x^3 = 0\)
\(x^2 (1 - x) = 0\)

\(x = 0\) or \(x =1\).


Answer: A
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135661 [0], given: 12705

Current Student
avatar
Joined: 30 Jul 2014
Posts: 4

Kudos [?]: 6 [0], given: 11

Location: United States
Concentration: Strategy, Finance
GMAT 1: 640 Q39 V38
GMAT ToolKit User
Re M02-32 [#permalink]

Show Tags

New post 15 Mar 2015, 11:46
I think this question is poor and not helpful.
How can statement (2) be correct if there are two value for x? (x= 0 & 1)

Kudos [?]: 6 [0], given: 11

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

Re: M02-32 [#permalink]

Show Tags

New post 15 Mar 2015, 13:12
KPMM07 wrote:
I think this question is poor and not helpful.
How can statement (2) be correct if there are two value for x? (x= 0 & 1)


Sorry, but it's not clear at all what you mean. There is nothing wrong with the question... Can you please elaborate?
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135661 [0], given: 12705

Manager
Manager
avatar
Joined: 02 May 2014
Posts: 116

Kudos [?]: 63 [0], given: 475

Schools: ESADE '16, HKU'16, SMU '16
GMAT 1: 620 Q46 V30
GMAT ToolKit User
Re: M02-32 [#permalink]

Show Tags

New post 20 Mar 2015, 06:17
KPMM07 wrote:
I think this question is poor and not helpful.
How can statement (2) be correct if there are two value for x? (x= 0 & 1)


Hi,

Thats exactly the reason why (2) is not correct. We will have two values for x^2.
when x= 0, x^2 = 0 and
when x = 1 , x^2 = 1

Hence (2) is insufficient.

Thanks!

Kudos [?]: 63 [0], given: 475

Manager
Manager
avatar
Joined: 02 May 2014
Posts: 116

Kudos [?]: 63 [0], given: 475

Schools: ESADE '16, HKU'16, SMU '16
GMAT 1: 620 Q46 V30
GMAT ToolKit User
Re: M02-32 [#permalink]

Show Tags

New post 20 Mar 2015, 06:19
sytabish wrote:
KPMM07 wrote:
I think this question is poor and not helpful.
How can statement (2) be correct if there are two value for x? (x= 0 & 1)


Hi KPMM07 ,

Thats exactly the reason why (2) is not correct. We will have two values for x^2.
when x= 0, x^2 = 0 and
when x = 1 , x^2 = 1

Hence (2) is insufficient.

Thanks!

Kudos [?]: 63 [0], given: 475

Current Student
avatar
B
Joined: 20 Mar 2014
Posts: 2672

Kudos [?]: 1789 [0], given: 797

Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
GMAT ToolKit User Premium Member Reviews Badge
Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 04:37
Bunuel wrote:
Official Solution:


Statement (1) by itself is sufficient. From Statement (1):
\(x^2 = 2x - 1\)
\(x^2 - 2x + 1 = 0\)
\((x-1)^2 = 0\)
\(x -1 = 0\)
\(x = 1\)

Thus, \(x^2 = 1\).

Statement (2) by itself is insufficient. From Statement (2):
\(x^2 - x^3 = 0\)
\(x^2 (1 - x) = 0\)

\(x = 0\) or \(x =1\).


Answer: A


Hi Bunuel

I have a problem with your analysis of statement (1). x=1 does not satisfy the given equation, x = (2)^0.5 *x -1.

Squaring the given equation will not give 'x^2 = 2x - 1' although it will give you a unique value of x that is real. Please check.

Thanks

Kudos [?]: 1789 [0], given: 797

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 04:44
Engr2012 wrote:
Bunuel wrote:
Official Solution:


Statement (1) by itself is sufficient. From Statement (1):
\(x^2 = 2x - 1\)
\(x^2 - 2x + 1 = 0\)
\((x-1)^2 = 0\)
\(x -1 = 0\)
\(x = 1\)

Thus, \(x^2 = 1\).

Statement (2) by itself is insufficient. From Statement (2):
\(x^2 - x^3 = 0\)
\(x^2 (1 - x) = 0\)

\(x = 0\) or \(x =1\).


Answer: A


Hi Bunuel

I have a problem with your analysis of statement (1). x=1 does not satisfy the given equation, x = (2)^0.5 *x -1.

Squaring the given equation will not give 'x^2 = 2x - 1' although it will give you a unique value of x that is real. Please check.

Thanks


Not sure what exactly are you doing there...

x=1 satisfies x^2 = 2x - 1: 1^1 = 2*1 - 1.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135661 [0], given: 12705

Intern
Intern
avatar
Joined: 13 Apr 2015
Posts: 2

Kudos [?]: [0], given: 0

Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 05:16
Bunuel wrote:
Engr2012 wrote:
Bunuel wrote:
Official Solution:


Statement (1) by itself is sufficient. From Statement (1):
\(x^2 = 2x - 1\)
\(x^2 - 2x + 1 = 0\)
\((x-1)^2 = 0\)
\(x -1 = 0\)
\(x = 1\)

Thus, \(x^2 = 1\).

Statement (2) by itself is insufficient. From Statement (2):
\(x^2 - x^3 = 0\)
\(x^2 (1 - x) = 0\)

\(x = 0\) or \(x =1\).


Answer: A


Hi Bunuel

I have a problem with your analysis of statement (1). x=1 does not satisfy the given equation, x = (2)^0.5 *x -1.

Squaring the given equation will not give 'x^2 = 2x - 1' although it will give you a unique value of x that is real. Please check.

Thanks


Not sure what exactly are you doing there...

x=1 satisfies x^2 = 2x - 1: 1^1 = 2*1 - 1.



How did you get from x = (2)^0.5 *x -1 to x^2 = 2x - 1?

Kudos [?]: [0], given: 0

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 05:20

Kudos [?]: 135661 [0], given: 12705

Current Student
avatar
B
Joined: 20 Mar 2014
Posts: 2672

Kudos [?]: 1789 [0], given: 797

Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
GMAT ToolKit User Premium Member Reviews Badge
Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 05:36
Bunuel wrote:
Engr2012 wrote:
Bunuel wrote:
Official Solution:


Statement (1) by itself is sufficient. From Statement (1):
\(x^2 = 2x - 1\)
\(x^2 - 2x + 1 = 0\)
\((x-1)^2 = 0\)
\(x -1 = 0\)
\(x = 1\)

Thus, \(x^2 = 1\).

Statement (2) by itself is insufficient. From Statement (2):
\(x^2 - x^3 = 0\)
\(x^2 (1 - x) = 0\)

\(x = 0\) or \(x =1\).


Answer: A


Hi Bunuel

I have a problem with your analysis of statement (1). x=1 does not satisfy the given equation, x = (2)^0.5 *x -1.

Squaring the given equation will not give 'x^2 = 2x - 1' although it will give you a unique value of x that is real. Please check.

Thanks


Not sure what exactly are you doing there...

x=1 satisfies x^2 = 2x - 1: 1^1 = 2*1 - 1.


Bunuel,

If x^2 =1 , then x = 1 or -1. Both these values do not satisfy the given equation in statement (1). When you square a linear equation, you need to check whether the solution(s) satisfy the given equation. If I have to treat this as a PS problem with only statement (1) as the question statement, then x^2=1 will not satisfy the original equation x = (2)^0.5 *x -1. Additionally, when you square this (statement 1) equation, you can not get "x^2 = 2x - 1".

Kudos [?]: 1789 [0], given: 797

Current Student
avatar
B
Joined: 20 Mar 2014
Posts: 2672

Kudos [?]: 1789 [0], given: 797

Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
GMAT ToolKit User Premium Member Reviews Badge
Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 05:40
Bunuel wrote:
hUserName wrote:

How did you get from x = (2)^0.5 *x -1 to x^2 = 2x - 1?


Square \(x = \sqrt{2x - 1}\) to get \(x^2 = 2x - 1\).


Bunuel

The way question is getting displayed, it seems that square root is with 2 only and not with the entire thing (x-1). Please re format the question so that the root is displayed as per your comment.

I think I got my answer to the doubt that I had.

Kudos [?]: 1789 [0], given: 797

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 05:41
Engr2012 wrote:
Bunuel,

If x^2 =1 , then x = 1 or -1. Both these values do not satisfy the given equation in statement (1). When you square a linear equation, you need to check whether the solution(s) satisfy the given equation. If I have to treat this as a PS problem with only statement (1) as the question statement, then x^2=1 will not satisfy the original equation x = (2)^0.5 *x -1. Additionally, when you square this (statement 1) equation, you can not get "x^2 = 2x - 1".


You are NOT correct.

If you square \(x = \sqrt{2x - 1}\) you get \(x^2 = 2x - 1\).
Next, if you substitute x=1 into \(x = \sqrt{2x - 1}\) the equation will hold true.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135661 [0], given: 12705

Intern
Intern
avatar
Joined: 13 Apr 2015
Posts: 2

Kudos [?]: [0], given: 0

Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 05:44
Bunuel wrote:
Engr2012 wrote:
Bunuel,

If x^2 =1 , then x = 1 or -1. Both these values do not satisfy the given equation in statement (1). When you square a linear equation, you need to check whether the solution(s) satisfy the given equation. If I have to treat this as a PS problem with only statement (1) as the question statement, then x^2=1 will not satisfy the original equation x = (2)^0.5 *x -1. Additionally, when you square this (statement 1) equation, you can not get "x^2 = 2x - 1".


You are NOT correct.

If you square \(x = \sqrt{2x - 1}\) you get \(x^2 = 2x - 1\).
Next, if you substitute x=1 into \(x = \sqrt{2x - 1}\) the equation will hold true.



I think the confusion is between 2^0.5*x-1 versus (2x-1)^(0.5), in the 2nd case the problem and solution as stated is correct...

Kudos [?]: [0], given: 0

Current Student
avatar
B
Joined: 20 Mar 2014
Posts: 2672

Kudos [?]: 1789 [0], given: 797

Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
GMAT ToolKit User Premium Member Reviews Badge
Re: M02-32 [#permalink]

Show Tags

New post 27 Apr 2015, 06:08
hUserName wrote:
Bunuel wrote:
Engr2012 wrote:
Bunuel,

If x^2 =1 , then x = 1 or -1. Both these values do not satisfy the given equation in statement (1). When you square a linear equation, you need to check whether the solution(s) satisfy the given equation. If I have to treat this as a PS problem with only statement (1) as the question statement, then x^2=1 will not satisfy the original equation x = (2)^0.5 *x -1. Additionally, when you square this (statement 1) equation, you can not get "x^2 = 2x - 1".


You are NOT correct.

If you square \(x = \sqrt{2x - 1}\) you get \(x^2 = 2x - 1\).
Next, if you substitute x=1 into \(x = \sqrt{2x - 1}\) the equation will hold true.


I think the confusion is between 2^0.5*x-1 versus (2x-1)^(0.5), in the 2nd case the problem and solution as stated is correct...


Yes. Exactly. I was checking for X=1 with the square root with 2 only and not the entire expression. It is not clear from the way the question is getting displayed.

Kudos [?]: 1789 [0], given: 797

Intern
Intern
avatar
Joined: 28 Oct 2013
Posts: 9

Kudos [?]: [0], given: 82

Concentration: Finance, General Management
GMAT 1: 720 Q49 V39
WE: Research (Investment Banking)
GMAT ToolKit User
Re: M02-32 [#permalink]

Show Tags

New post 28 Apr 2015, 10:14
hi Bunuel
can you please solve my query? if x^2= x^3, does not it imply that X is Positive? then that would eliminate 0 as a possibility, making statement 2 sufficient. please tell me where i am going wrong.

Kudos [?]: [0], given: 82

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42607

Kudos [?]: 135661 [0], given: 12705

Re: M02-32 [#permalink]

Show Tags

New post 29 Apr 2015, 01:10
djonga wrote:
hi Bunuel
can you please solve my query? if x^2= x^3, does not it imply that X is Positive? then that would eliminate 0 as a possibility, making statement 2 sufficient. please tell me where i am going wrong.


x^2 = x^3;

x^2 - x^3 = 0;

x^2(1 - x) = 0;

x = 0 or x = 1.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135661 [0], given: 12705

Intern
Intern
avatar
Joined: 14 Oct 2015
Posts: 37

Kudos [?]: 19 [0], given: 0

GMAT 1: 640 Q45 V33
Re M02-32 [#permalink]

Show Tags

New post 17 Oct 2015, 13:00
I think this is a high-quality question and I agree with explanation. Why can't I divide both sides of statement 2 by X^2?? This would take me to X=1 and make the statement sufficient.

Kudos [?]: 19 [0], given: 0

Current Student
avatar
B
Joined: 20 Mar 2014
Posts: 2672

Kudos [?]: 1789 [0], given: 797

Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
GMAT ToolKit User Premium Member Reviews Badge
Re: M02-32 [#permalink]

Show Tags

New post 17 Oct 2015, 13:45
danjbon wrote:
I think this is a high-quality question and I agree with explanation. Why can't I divide both sides of statement 2 by X^2?? This would take me to X=1 and make the statement sufficient.



You can not divide by x^2 as you don't know whether x=0 or not. Statement 2 is also satisfied by x=0. Be careful with dividing by variables when you either don't know the sign or the values.

Dividing by x^2 implies that you are assuming x can't be =0

Kudos [?]: 1789 [0], given: 797

Intern
Intern
avatar
Joined: 05 Oct 2015
Posts: 7

Kudos [?]: [0], given: 103

M02-32 [#permalink]

Show Tags

New post 18 Jul 2016, 10:58
Bunuel wrote:
djonga wrote:
hi Bunuel
can you please solve my query? if x^2= x^3, does not it imply that X is Positive? then that would eliminate 0 as a possibility, making statement 2 sufficient. please tell me where i am going wrong.


x^2 = x^3;

x^2 - x^3 = 0;

x^2(1 - x) = 0;

x = 0 or x = 1.


Hi Bunuel,

x^2 = x^3.

why can't we just divide by x^2 to get x = 1?

What am I missing here? I see how both 0 and 1 are solutions but what theorem am I missing? I feel like it is basic and I may just be forgetting.

EDIT: Never mind previous poster answered it.

Kudos [?]: [0], given: 103

M02-32   [#permalink] 18 Jul 2016, 10:58

Go to page    1   2    Next  [ 28 posts ] 

Display posts from previous: Sort by

M02-32

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderators: chetan2u, Bunuel



GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.