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Re M18-35 [#permalink]
I think this is a high-quality question and the explanation isn't clear enough, please elaborate. If I put 0 at the original equation, I have it correct, why 0 is not a root?
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Re: M18-35 [#permalink]
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blonpina wrote:
I think this is a high-quality question and the explanation isn't clear enough, please elaborate. If I put 0 at the original equation, I have it correct, why 0 is not a root?

The explanation is clear and elaborate enough.

If x = 0, then ­\(2-x^2 = (x-2)^2\) becomes:

­\(2-0^2 = (0-2)^2\)

­\(2 = (-2)^2\)

­\(2 = 4\)

The above is not correct. Hence, 0 is not a solution. 
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Re: M18-35 [#permalink]
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