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16 May 2024, 01:02
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Question Stats:
100% (01:16) correct
0% (00:00) wrong based on 2 sessions
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Machine R, working alone at a constant rate, produces x units of a product in 30 minutes, and machine S, working alone at a constant rate, produces x units of the product in 48 minutes, where x is a positive integer.
Quantity A
The number of units of the product that machine R, working alone at its constant rate, produces in 3 hours
Quantity B
The number of units of the product that machine S, working alone at its constant rate, produces in 4 hours
Quantity A
The number of units of the product that machine R, working alone at its constant rate, produces in 3 hours
Quantity B
The number of units of the product that machine S, working alone at its constant rate, produces in 4 hours
19 May 2024, 12:34
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Let X is 1.
Number of units by A in 3 hours = \(\frac{180 min}{30 min}\)= 6
Number of units by B in 4 hours = \(\frac{240 min}{48 min}\)= 5
Hence, option \(A\) is greater.
Number of units by A in 3 hours = \(\frac{180 min}{30 min}\)= 6
Number of units by B in 4 hours = \(\frac{240 min}{48 min}\)= 5
Hence, option \(A\) is greater.
13 Jul 2024, 11:05
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Official Explanation
In this question you are given that machine R, working alone at its constant rate, produces x units of a product in 30 minutes. Since it is easy to see that 3 hours is 6 times 30 minutes, you can conclude that Quantity A is 6x.
You can compare 6x with Quantity B in two ways.
One: In the additional information centered above the quantities, you are given that machine S, working alone at its constant rate, produces x units of the product in 48 minutes, so you can conclude that machine S can produce 6x units of the product in (6)(48) minutes, or 4.8 hours. So in 4 hours, machine S produces less than 6x units, and Quantity B is less than 6x.
Two: First, convert 48 minutes to 4/5 hour, then find the number of 48-minute periods there are in 4 hours by computing 4/(4/5) = 4(5/4) = 5 Thus, Quantity B is 5x.
Either way, Quantity A is greater than Quantity B, and the correct answer is Choice A.
In this question you are given that machine R, working alone at its constant rate, produces x units of a product in 30 minutes. Since it is easy to see that 3 hours is 6 times 30 minutes, you can conclude that Quantity A is 6x.
You can compare 6x with Quantity B in two ways.
One: In the additional information centered above the quantities, you are given that machine S, working alone at its constant rate, produces x units of the product in 48 minutes, so you can conclude that machine S can produce 6x units of the product in (6)(48) minutes, or 4.8 hours. So in 4 hours, machine S produces less than 6x units, and Quantity B is less than 6x.
Two: First, convert 48 minutes to 4/5 hour, then find the number of 48-minute periods there are in 4 hours by computing 4/(4/5) = 4(5/4) = 5 Thus, Quantity B is 5x.
Either way, Quantity A is greater than Quantity B, and the correct answer is Choice A.
