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3x + 5y= -2
rearranging the equation:
y=-(3/5)x-(2/5)
slope is negative
line passes through either II,I ,and IV quadrants or II,III, and IV quadrants.
Y intercept is negative => line passes through II,III and IV quadrants.
Any point (x,y) in I quadrant will not satisfy the given equation.

Answer: B
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Bunuel

In the rectangular quadrant system shown above, which quadrant, if any, contains no point (x, y) that satisfies the equation 3x + 5y = −2?

A. none
B. I
C. II
D. III
E. IV

Attachment:
2016-08-08_2014.png

3x + 5y = -2

Put x = 0, y = -2/5
Put y = 0, x = -2/3

Plot the two points. You will see that the line will pass through II, III and IV quadrants but not through quadrant I.

Answer (B)

Also note that a line cannot pass through all 4 quadrants...
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The equation is 3x + 5y = -2. Since both x and y are positive in the 1st quadrant, sum of 2 positive numbers can never yield a negative.

Answer (B.)
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Hello from the GMAT Club BumpBot!

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