Last visit was: 31 Oct 2024, 16:20 It is currently 31 Oct 2024, 16:20
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
LUCIFER1703
Joined: 06 Jan 2018
Last visit: 13 Dec 2022
Posts: 28
Own Kudos:
124
 [16]
Given Kudos: 51
Location: India
Schools: AIM '22 (A)
Schools: AIM '22 (A)
Posts: 28
Kudos: 124
 [16]
6
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 31 Oct 2024
Posts: 19,675
Own Kudos:
23,711
 [5]
Given Kudos: 287
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 19,675
Kudos: 23,711
 [5]
3
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
lucajava
Joined: 21 Feb 2019
Last visit: 18 Jul 2019
Posts: 69
Own Kudos:
315
 [1]
Given Kudos: 67
Location: Italy
Posts: 69
Kudos: 315
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
prashanths
Joined: 27 May 2010
Last visit: 19 Jun 2020
Posts: 105
Own Kudos:
263
 [2]
Given Kudos: 22
Posts: 105
Kudos: 263
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Emma should be there on the list. So start with Emma and choosing 3 out of the remaining 5 would be in 5P3 ways.

Then, arranging the list with Emma at the remaining 3 places in the list would be 5P3*4 = 240.
So option C
User avatar
ahamd
Joined: 25 Feb 2015
Last visit: 26 Jun 2024
Posts: 19
Own Kudos:
2
 [1]
Given Kudos: 148
Posts: 19
Kudos: 2
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
LUCIFER1703
Lyndsy has six novels she wants to read, One of which is Emma, She plans to create a reading list of four of these novels for an upcoming trip, and different orders count as different lists. How many readings list are possible if Emma has to be on the list.

A 60
B 120
C 240
D 360
E 6

Please hit a Kudos if you like the post.

Out of 4 novels,Emma is already selected.Hence we need to select 3 out of the remaining 5 novels in 5C3 ways..Now the total 4 novels can also be arranged in 4! ways..No of arrangements will be 5c3* 4!=10*24=240 ways
User avatar
TPW
Joined: 20 Nov 2022
Last visit: 28 May 2024
Posts: 13
Own Kudos:
Given Kudos: 54
Location: India
GMAT 1: 730 Q50 V38
GPA: 3.5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Different than above given ways to solve thus:

1. Different ways to create reading list of 4 books out of 6 = 6x5x4x3 = 360 ways

2. Different ways to create a reading list of 4 books out of 5 books (excluding Emma)
5x4x3x2 =120 ways

Different ways in which Emma is on the list of 4 books

(1) - (2) = 360-120 =240

Posted from my mobile device
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 35,330
Own Kudos:
Posts: 35,330
Kudos: 902
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderator:
Math Expert
96533 posts