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Bunuel
If \(xyz > 0\), is \(x(y^2)(z^3) > 0\) ?

(1) \(y > 0\)
(2) \(x > 0\)

Please enlighten me here
From (1) we get that Y>0
That means X and Z both will be either positive or negative
If both are positive in that case x(y^2)(z^3) > 0 -----True
If both are negative in that case x(y^2)(z^3) > 0 -----True

So in my opinion 1 is sufficient.
Please correct my flaws
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Here option A is correct as ,if Y>0
then either a and z both are positive or both are negative as xyz >0.
In the both the conditions xy^2z^3 will be postiive.
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If xyz>0, is x(y^2)(z3)>0?

Since xyz > 0, there are two possibilities:
1. (+)(+)(+) OR
2. (+)(-)(-)

We need to see what happens to these scenarios given the ranges below.

(1) y>0
Scenario 1 checks out if all three are positive so x(y^2)(z3)>0
Scenario 2 checks out if y is positive, but x and z are negative so x(y^2)(z3)>0
Sufficient.

(2) x>0
Scenario 1 checks out if all three are positive so x(y^2)(z3)>0
Scenario 2 does not check out because y^2 ends up positive so you get (+)(+)(-) so x(y^2)(z3) <0.
Insufficient.
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xyz>0

Question: x(y^2)(z^3)>0 ??? as we know that x(y^2)(z^3) = xyz(yz^2),
We can rephrase the Question as: xyz(yz^2)>0???

Given that xyz>0 (+) and z^2>0 (+) we only need to know the sign value of y.

Answer A
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Hello from the GMAT Club BumpBot!

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