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stonecold
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GRE 1: Q169 V154
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For two similar triangles => If the side ratio is k then the ratio of their areas is k^2

Hence k^2=> 81/16 => k=9/4

The ratio of their perimeters => 9/4 too.

Smash that D.
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stonecold
For two similar triangles => If the side ratio is k then the ratio of their areas is k^2

Hence k^2=> 81/16 => k=9/4

The ratio of their perimeters => 9/4 too.

Smash that D.

I don't quite understand.

Area/area = Side^2 / side^2 = 9^2 / 4^4

So one side of the larger triangle is 9 and the other triangle has a side of 4.

Why does it necessarily follow that the perimeter is in this ratio?
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CEdward
stonecold
For two similar triangles => If the side ratio is k then the ratio of their areas is k^2

Hence k^2=> 81/16 => k=9/4

The ratio of their perimeters => 9/4 too.

Smash that D.

I don't quite understand.

Area/area = Side^2 / side^2 = 9^2 / 4^4

So one side of the larger triangle is 9 and the other triangle has a side of 4.

Why does it necessarily follow that the perimeter is in this ratio?

Think about it: If sides of a larger similar triangle is k times the sides of a smaller triangle (with sides a, b and c), the sides of the larger triangle will be ka, kb and kc.
So perimeter = ka + kb + kc = k(a + b + c)

So perimeter of the greater triangle will also be k times the perimeter of the smaller triangle.
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