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10 Apr 2017, 20:20
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:13) correct
20%
(01:42)
wrong
based on 128
sessions
History
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Two similar triangles have areas in the ratio 81:16. What is the ratio of their perimeters?
A)81:16
B)9:16
C)9:8
D)9:4
E)3:2
A)81:16
B)9:16
C)9:8
D)9:4
E)3:2
11 Apr 2017, 05:20
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stonecold
This is the property of similar triangles: If the ratio of sides of two similar triangles is \(a:b\), the ratio of their areas is \(a^2:b^2\).
This is discussed in detail here:
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2014/0 ... -the-gmat/
Since the areas of the given two triangles are in the ratio 81:16, the ratio of their sides will be 9:4.
So the sides will be 9a, 9b, 9c and 4a, 4b, 4c.
Perimeter of the triangles will be in the ratio (9a + 9b + 9c) : (4a + 4b + 4c) = 9:4
Answer (D)
General Discussion
