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This question is discussed here: when-a-certain-rubber-ball-is-dropped-it-rebounds-75-percent-as-high-420055.html

Thanks Bunuel

Can anyone send link for more Gmat prep questions

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Hi Guys any idea what to revise a day before the exam, I am not sure what all to revise as so much has been covered.

There is not much you should do. Just make sure the big items are squared away - strategies, timing. Scratch paper etc

This should still be relevant: what-to-do-30-14-7-3-1-days-before-the-test-152506.html

Data Sufficiency Butler: April 2024
April 15	DS 1	DS 2

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Problem Solving Butler: April 2023
April 15	PS 1	PS 2

hey, here shouldn’t the ans be 10,000(0.8)^9? Is there something Im missing?

A certain machine, which had an original value of $10,000 when purchased new, depreciated in value each year for 9 years. For each year after the machine was purchased, its value was at most 80 percent of its value the previous year. What was the maximum possible value, in thousands of dollars, of the machine 9 years after it was purchased?

A. \((10*0.8)^8\)
B. \((10*0.8)^9\)
C. \(10(0.8)^8\)
D. \(10(0.8)^9\)
E. \(10(0.8)^{10}\)


To find the maximum possible value, let’s assume the value of the machine was exactly 80% of its value from the previous year, not less. Then, its value in 9 years would be $10,000 * 0.8^9. However, note that the question asks for the value in thousands of dollars. Therefore, expressed in thousands of dollars, the value is 10 * 0.8^9.

Answer: D.

Posted here:
a-certain-machine-which-had-an-original-value-of-10-000-when-428586.html
Hope this helps.

Hi guys! Can anyone help explain how they got to right answer here for these two overlapping set questions? My approach is the matrix but I can’t seem to get to the right answer. This is OG Practice Exam

For the second one
Use the Venn diagram

N=400
Given a watch =260
Given a phone 80
Given both X = 1/2 Y
Neither received any of =Y

400= (260-1/2Y) + (80-1/2Y) -(1/2Y)+Y
340+1/2Y=400
1/2Y=60

We want to find how many received only what (260-1/2Y)
The 260-1/2Y=260-60=200

Any idea for the 1st one
By using the Venn diagram
How to arrive at the possible n interval

171 stores(90percent)
76 stores that rent
Y store that do both

We will find Ymax and Y min
Ymin = 247-190=57
Ymax has to be less than the lesser value (76 stores)
57<= Y<=76
How to conclude for n

thanks, not sure where the 247 came from

Here is my take on the first question.
First -> the max limit of n

Next -> The min limit of n

Multiple ways of solving the question. This is one

Question 2 - I think the answer should be 200.

1st question is discussed here: of-the-400-employees-in-a-certain-office-260-have-been-given-a-watch-415750.html

2nd question is discussed here: of-the-190-bicycle-stores-in-a-certain-region-90-percent-repair-414730.html

Hope this helps.