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The surface area of cylinder A is how many times the surface area of

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Re: The surface area of cylinder A is how many times the surface area of [#permalink]
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Bunuel wrote:
The surface area of cylinder A is how many times the surface area of cylinder B?

(1) The diameter of A is twice the diameter of B.
(2) The height of A is equal to the height of B.

Total Surface Area of a Cylinder = $$2 * \pi * r^2 + 2 * \pi * r * h$$
= $$2 \pi r (r + h)$$

Statement 1 and Statement 2 are individually not sufficient as only one aspect of the dimension is provided.

Combined

Cylinder A :
• Height = h

Cylinder B:
$$\frac{TSA_A }{ TSA_B} = \frac{2 \pi *2r (2r + h) }{ 2 \pi r (r + h)}$$
$$\frac{TSA_A }{ TSA_B} = \frac{2(2r + h) }{ (r + h)}$$