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# The weights of all dishes of type X are exactly the same, and the weig

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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
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St I )

3x + 2y < 2x + 4y
Implies x<2y . INSUFF

St II) 4x + 3y < 3x +4y, implies
x < y. SUFF. Hence B
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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
Statement1: For those who hate picking numbers just like me: 3X + 2Y < 2X + 4Y --> x<2y --> x/2<y --> Thus y could be less than x, equal to x or greater than x. Not sufficient
St2: is quite straight forward. Sufficient

B it is!
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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
I don't get it. x<2y, if x =2, and y=3 then 2<2(3) = 2 <6 thus y is greater than x
on the other hand, if x=3 and y = 2 then 3<2(2) = 3<4 thus y is still greater than x. M I missing the point ? I don't understand why you thing if x=3, and y=2 will make the first statement insufficient.
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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
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mawus wrote:
I don't get it. x<2y, if x =2, and y=3 then 2<2(3) = 2 <6 thus y is greater than x
on the other hand, if x=3 and y = 2 then 3<2(2) = 3<4 thus y is still greater than x. M I missing the point ? I don't understand why you thing if x=3, and y=2 will make the first statement insufficient.

Statement 1:
X < 2Y

if x=2, and y=3
3 < 2*3 true
2<3 true

if x=3 and y=2
3 < 2*2 true
but 3 is not < 2

we have 2 conflicting pieces of information, so Statement 1 is insufficient
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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
Thank you it make sense
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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
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Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?

(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y.
(2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.

Solution:

We are given that we have two types of dishes, dish X and dish Y, and each dish of each type has the same weight. We are asked whether the weight of 1 dish of type X is less than the weight of 1 dish of type Y. If we let X and Y denote the weights of dishes X and Y, respectively, then we can restate the question as:

Is X < Y ?

Statement One Alone:

The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y.

Using the information from statement one we can set up the following inequality:

3X + 2Y < 2X + 4Y

X < 2Y

We see that the weight of 1 dish of type X is less than the combined weight of 2 dishes of type Y. However we can’t tell whether the weight of 1 dish of type X is less than the weight of 1 dish of type Y. This is not enough information to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.

Using the information from statement two we can set up the following inequality:

4X + 3Y < 3X + 4Y

X < Y

We see that this answers the question.

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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
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Re: The weights of all dishes of type X are exactly the same, and the weig [#permalink]
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