Bunuel
Two workers, A and B, completed a job in 10 days, but A did not work during the last 2 days. In the first 7 days they together completed 4/5 of the job. How long would A take to do the job alone?
A. 16 days
B. 15 days
C. 14 days
D. 13 days
D. 12 days
Total \(10 \) days - in which \(8\) days were together and \(2\) days B worked alone
Given \(7\) days working together - \(\frac{4}{5} \) work done
\(1 \) day working together \(= \frac{4}{35}\) work done
in \(8\) days working together \(= \frac{4 *8 }{35}= \frac{32}{35} \)
Hence in Last two days ONLY B worked and completed remaining \(\frac{3}{35} \)
B will do whole work alone in \(= \frac{35 *2 }{3} = \frac{70}{3}\) days.
Hence B's rate \(= \frac{3}{70}\)
We know in \(7\) days \(\frac{4}{5} \) work was done :
This can be represented by:
Hence \(\frac{1}{A}+\frac{1}{B} = \frac{4}{35} \)
\(\frac{1}{A}+ \frac{3}{70}= \frac{4}{35}\)
\(\frac{1}{A} = \frac{4}{35} - \frac{3}{70}\)
\(\frac{1}{A}=\frac{1}{14}\)
\(A=14\)
Ans C