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Walking at 60% of his usual speed a man takes 24 minutes more to cover
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Bunuel
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Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  08 Dec 2015, 02:06
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Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?

A. 30
B. 36
C. 42
D. 48
E. 54
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Bunuel
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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  26 Nov 2021, 01:57
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Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?

A. \(30\)
B. \(36\)
C. \(42\)
D. \(48\)
E. \(54\)


Say the usual speed and the usual time are \(s\) and \(t\), respectively. Then the distance is \(d=st\).

The distance can also be expressed as \(d=(0.6s)(t+24)\)

Equate: \(st=(0.6s)(t+24)\);

Reduce by \(s\) and solve to get \(t=36\).


Answer: B
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Psiva00734
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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  08 Dec 2015, 02:15
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speed is inversly proprtional to time

walking at 60% of speed meand 3/5s takes 5/3t.
It takes 24 minutes extra to cover the distance. then

5/3t=t+24

5t=3t+72

2t=72

t=36.


Option B is correct
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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  08 Dec 2015, 02:17
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walking at 60% of his usual speed =3/5
since speed is inversely proportional to time
time taken =5/3
now 5/3 =(1+2/3)
an increase of 2/3=24 minutes
therefore usual time =24*3/2=36 minutes
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gracie
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Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  08 Dec 2015, 15:40
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rt=.6r(t+24)
4t=144
t=36 minutes
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ishaan.wares
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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  07 May 2017, 02:41
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time is inverse to speed
60% reduce speed= (100-60) or 40% more time
40%=24
100%=60
usual time=60-24=36
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generis
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Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  08 May 2017, 05:47
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Bunuel wrote:
Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?

A. 30
B. 36
C. 42
D. 48
E. 54

Another way: To use r*t=D with just one variable, choose a number that's easily multiplied by .6 for normal rate

1. Let 10 (mi per min) be his normal rate
Slower rate is 60% of 10 = 6 (mi per min)

2. Let x be normal time, and (x+24) be longer time.

3. r*t = D

Normal: 10*x = D
Slower: 6*(x+24) = D

4.Ds are equal, so

10x = 6x+144
4x=144, so
x = 36
Answer B
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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  03 Apr 2018, 09:23
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Bunuel wrote:
Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?

A. 30
B. 36
C. 42
D. 48
E. 54


Let's start with a WORD EQUATION:
distance traveled at REGULAR speed = distance traveled at REDUCED speed

distance = (rate)(time)
Let R = REGULAR speed
So 0.6R = REDUCED speed
Let t = travel time (in minutes) at REGULAR speed
So t + 24 = travel time (in minutes) at REDUCED speed

Now plug this information into our WORD EQUATION to get:
Rt = (0.6R)(t + 24)
Divide both sides by R to get: t = (0.6)(t + 24)
Rewrite 0.6 as 3/5 to get: t = (3/5)(t + 24)
Expand: t = 3t/5 + 72/5
Multiply both sides by 5 to get: 5t = 3t + 72
Solve to get: t = 36

Answer: B

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Brent
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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink] New post  20 May 2021, 22:35
Bunuel wrote:
Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?

A. 30
B. 36
C. 42
D. 48
E. 54


We know, \(Speed ∝\frac{1}{time}\)

60%=3/5
Let, his usual speed be x. If his speed is x, time taken is 1/x, if his speed is 3x/5 then the time taken is 5x/3.

Here, late time~usual time = 24 minute
So, 5x/3~x=25
=>x=36 minute.

Answer is B

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Re: Walking at 60% of his usual speed a man takes 24 minutes more to cover [#permalink]
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