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24 Dec 2013, 03:42
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:01) correct
10%
(01:15)
wrong
based on 1313
sessions
History
Date
Time
Result
Not Attempted Yet
What is the average (arithmetic mean) of x and y?
(1) The average of x and 2y is 10.
(2) The average of 2x and 7y is 32.
(1) The average of x and 2y is 10.
(2) The average of 2x and 7y is 32.
24 Dec 2013, 03:43
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SOLUTION
What is the average (arithmetic mean) of x and y?
The average (arithmetic mean) of x and y is \(\frac{x+y}{2}\). Thus we need to find the value of x+y.
(1) The average of x and 2y is 10 --> \(\frac{x+2y}{2}=10\). Not sufficient.
(2) The average of 2x and 7y is 32 --> \(\frac{2x+7y}{2}=32\). Not sufficient.
(1)+(2) We have two distinct linear equations with two unknowns, thus we can solve for both and get the value of x+y. Sufficient.
Answer: C.
What is the average (arithmetic mean) of x and y?
The average (arithmetic mean) of x and y is \(\frac{x+y}{2}\). Thus we need to find the value of x+y.
(1) The average of x and 2y is 10 --> \(\frac{x+2y}{2}=10\). Not sufficient.
(2) The average of 2x and 7y is 32 --> \(\frac{2x+7y}{2}=32\). Not sufficient.
(1)+(2) We have two distinct linear equations with two unknowns, thus we can solve for both and get the value of x+y. Sufficient.
Answer: C.
General Discussion
25 Dec 2013, 10:55
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The question asks for average of x and y: (x+y)/2. So, it is sufficient if we know the values of x and y individually or (x+y) as a whole.
With either statements alone, it is not possible to arrive at (x+y) value.
When both statements are together, we can find out the (x+y) value since we have 2 equations and 2 unknowns.
Hence (C) is the answer.
With either statements alone, it is not possible to arrive at (x+y) value.
When both statements are together, we can find out the (x+y) value since we have 2 equations and 2 unknowns.
Hence (C) is the answer.
