Bunuel wrote:
What is the distance between the points (–2, –2) and (4, 6)?
(A) \(6\)
(B) \(7\)
(C) \(8\)
(D) \(10\)
(E) \(8\sqrt{2}\)
I'd typically use the same approach that Abhishek009 used
However, another approach is to sketch the points and then create a right triangle as follows:
At this point, we can either use the Pythagorean Theorem to determine the length (of the hypotenuse), or recognize that we have an an enlarged version of the Pythagorean triplet 3-4-5
In our diagram, the length of the triangle's legs (6 and 8) are TWICE the measurements of 3 and 4.
So, the length of the third side must be TWICE the measurements of remaining side (5)
In either case, we find the length to be 10
Answer: D
Cheers,
Brent
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