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# What is the distance between the points (–2, –2) and (4, 6)?

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What is the distance between the points (–2, –2) and (4, 6)? [#permalink]
Bunuel wrote:
What is the distance between the points (–2, –2) and (4, 6)?

(A) $$6$$

(B) $$7$$

(C) $$8$$

(D) $$10$$

(E) $$8\sqrt{2}$$

The distance between any two points (x1,x2) and (y1,y2) on the coordinate plane can be computed using the formula $$\sqrt{(x2-x1)^2 + (y2-y1)^2}$$

In this question the coordinates are (–2, –2) and (4, 6). Plugging values into the formula we get:
$$\sqrt{(4-(-2))^2 + (6-(-2))^2}$$
$$\sqrt{(4+2)^2 + (6+2)^2}$$
$$\sqrt{(6)^2 + (8)^2}$$
$$\sqrt{36 + 64}$$= $$\sqrt{100}$$ = $$10$$

Ans. D
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Re: What is the distance between the points (2, 2) and (4, 6)? [#permalink]
Bunuel wrote:
What is the distance between the points (–2, –2) and (4, 6)?

(A) $$6$$

(B) $$7$$

(C) $$8$$

(D) $$10$$

(E) $$8\sqrt{2}$$

We can use the distance formula:

Distance = root[(4 - (-2))^2 + (6 - (-2))^2]

Distance = root[(4 + 2)^2 + (6 + 2)^2]

Distance = root[( 6)^2 + (8)^2]

Distance = root[36 + 64]

Distance = root(100) = 10