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Re: What is the reminder when n^2 is divided by 4?
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18 Mar 2018, 23:15
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Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 1 variable (n) and 0 equations, D is most likely to be the answer. So, we should consider each of the conditions on their own first.
Condition 1)
Plugging-in numbers is suggested for remainder questions.
The integers which have a remainder of 1 when divided by 2 are odd.
So,
\(n: 1, 3, 5, 7, 9, …\)
and
\(n^2: 1, 9, 25, 49, 81, …\)
Each value of \(n^2\) has a remainder of \(1\) when it is divided by \(4\).
So, condition 1) is sufficient.
Condition 2)
When \(n = 1, n^2= 1\) has a remainder of \(1\) when it is divided by \(4.\)
When \(n = 4, n^2=16\) has a remainder of \(0\) when it is divided by \(4\).
Since we don’t have a unique answer, condition 2) is not sufficient.
Therefore, A is the answer.
Answer: A
If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.