Last visit was: 17 Jun 2024, 03:11 It is currently 17 Jun 2024, 03:11
Toolkit
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# Which of the following is a solution for the above equation

SORT BY:
Tags:
Show Tags
Hide Tags
Math Expert
Joined: 02 Sep 2009
Posts: 93718
Own Kudos [?]: 632400 [2]
Given Kudos: 82322
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6814
Own Kudos [?]: 30567 [1]
Given Kudos: 799
Current Student
Joined: 24 Nov 2021
Posts: 38
Own Kudos [?]: 15 [0]
Given Kudos: 92
Location: Argentina
Manager
Joined: 13 Jun 2019
Posts: 198
Own Kudos [?]: 94 [0]
Given Kudos: 645
GMAT 1: 490 Q42 V17
GMAT 2: 550 Q39 V27
GMAT 3: 630 Q49 V27
Re: Which of the following is a solution for the above equation [#permalink]
lucasdachequi
|3(-2.5) - 3| = |-7.5-3| = |-10.5| = 10.5..... not 4.5
VP
Joined: 10 Jul 2019
Posts: 1391
Own Kudos [?]: 559 [0]
Given Kudos: 1656
Which of the following is a solution for the above equation [#permalink]
Step 1: you can find the critical points on the number line, below which and above which the sign of the quantity inside the Modulus will change

|x - (-2)| + 2 |x - (-3)| + 3 |x - (+1)| = 12

The critical points: x = -3 , -2 , +1

{—————(-3)————(-2)—————(+1)——}

2nd) if you look at the answer choices, answers B, C, D, and E all fall with the range of greater than -2 and less than or equal to +1

Only answer A falls within a different range:

-3 </= x < -2

So let’s open the absolute value expressions according to this assumed range (if the answer doesn’t match A, then we can open the expressions according to the other range):

- (x + 2) + 2x + 6 - (3x - 3) = 12

-x - 2 + 2x + 6 - 3x + 3 = 12

-2x + 7 = 12

-2x = 5

X = 5 / -2 = (-) 5/2