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[[({1/4}^1/2)({1/4}^1/2)]^1/2]^2 =

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[[({1/4}^1/2)({1/4}^1/2)]^1/2]^2 =  [#permalink]

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New post 29 Aug 2019, 07:42
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

85% (00:47) correct 15% (00:46) wrong based on 39 sessions

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\((\sqrt{(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})})^2\)

A. \(\frac{1}{8}\)

B. \(\frac{1}{4}\)

C. \(\sqrt{\frac{1}{4}}\)

D. \(\sqrt{\frac{1}{2}}\)

E. 1

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New post 29 Aug 2019, 07:43
Bunuel please fix this one too

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New post 29 Aug 2019, 07:48
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New post 29 Aug 2019, 07:49
You are absolutely right ! Very tough one.

Bunuel wrote:
SajjadAhmad wrote:
Bunuel please fix this one too

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5.jpg


Fixed. That was a tough one.

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Re: [[({1/4}^1/2)({1/4}^1/2)]^1/2]^2 =  [#permalink]

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New post 29 Aug 2019, 07:57
SajjadAhmad wrote:
\((\sqrt{(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})})^2\)

A. \(\frac{1}{8}\)

B. \(\frac{1}{4}\)

C. \(\sqrt{\frac{1}{4}}\)

D. \(\sqrt{\frac{1}{2}}\)

E. 1


solve bracket by bracket
\((\sqrt{(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})})^2\)
(\sqrt{\frac{1}{4}})(\sqrt{\frac{1}{4}})}
1/2*1/2; 1/4
IMO B
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New post 29 Aug 2019, 08:00
Is it 1/4? That's what I got.
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New post 29 Aug 2019, 08:51
√1/4 *√1/4=1/4
(√1/4)^2=1/2 ^2=1/2 * 1/2=1/4
Option B

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Re: [[({1/4}^1/2)({1/4}^1/2)]^1/2]^2 =   [#permalink] 29 Aug 2019, 08:51
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