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GMATD11
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Both the numbers are divisible by 11

So it reduces to:
273/182

Now both the numbers are divisible by 13

21/14

Now both are divisible by, yes, 7

3/2

1.5
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GMATD11
3.003/2.002 =

A. 1.05
B. 1.50015
C. 1.501
D. 1.5015
E. 1.5

Given that 3.003/2.002
= 3003/2002
= (3*1001)/(2*1001)
= 3/2
1.5

Hence option E.
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(3.003)/(2.002)=(3+0.003)/(2+0.002)=(3+3х10^(-3))/(2+2х10^(-3))=3(1+10^(-3))/2(1+10^(-3))=3/2=1.5. Hope it is clear
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GMATD11
3.003/2.002 =

A. 1.05
B. 1.50015
C. 1.501
D. 1.5015
E. 1.5


3.003/2.002 = 3003/2002 = 3x1001 / 2x1001 = 3/2 = 1.5
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GMATD11
3.003/2.002 =

A. 1.05
B. 1.50015
C. 1.501
D. 1.5015
E. 1.5

There's a nice property of fractions that says: AB/CD = (A/C)(B/D)

Now notice that 3.003 = (3)(1.001)
And 2.002 = (2)(1.001)

So......3.003/2.002 = (3)(1.001)/(2)(1.001)
= (3/2)(1.001/1.001) [applying the above rule]
= (3/2)(1)
= 3/2
Answer:
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rewrite the fraction:
3.003
2.002
=3+.003
2+.002
=3+3*10^(-3)
2+2*10^(-3)
Factor:
3(1+10^(-3))
2(1+10^(-3))
=3/2
=1.5 answer E.
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GMATD11
3.003/2.002 =

A. 1.05
B. 1.50015
C. 1.501
D. 1.5015
E. 1.5

Gone for simple decimal division...
3.003/2.002= Step 1= 3003*10^3/2002*10^3
Step 2= 3003/2002 (10^3 crossed out)
answer: 1.5.
I hope its right and would be happy if anybody confirms me.
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GMAT is here simply trying to scare us off by adding unnecessary decimals, turns out it is very simple

3.003/ 2.002 = 3003/2002 = 3 ( 1001) / 2 (1001) = 3/2 = 1.5
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Another way to look at this problem is solving conceptually. That is, both denumerator and numerator are increased by the same proportion ( by 1/1000), hence the result of 3/2 won't change.
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GMATD11
3.003/2.002 =

A. 1.05
B. 1.50015
C. 1.501
D. 1.5015
E. 1.5

3.003/2.002 = 3003/2002 = 3/2= 1.5

ANSWER: E
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3.003
2.002

33 * 10*10*10
22* 10*10*10


Therefore, 33/22 = 1.5. Option (E)
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Bunuel

Can this equation be solved as below?


\(\frac{3}{2}=1.5\).

&
\(\frac{0.003}{0.002}=1.5\).


Bunuel
GMATD11
143) 3.003/2.002=

a) 1.05
b) 1.50015
c) 1.501
d) 1.5015
e) 1.5

\(\frac{3.003}{2.002}=\frac{3*1.001}{2*1.001}=1.5\).

Answer: E.
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GMATD11
3.003/2.002 =

A. 1.05
B. 1.50015
C. 1.501
D. 1.5015
E. 1.5
\(\frac{3.003}{2.002}\) ~ \(\frac{3}{2} = 1.5\) , Answer must be (E)
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