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I am not sure I understood the problem though. If they are asking us to find all the five integers so that the sum can be inferred, we certainly need more equations (5 equns to solve 5 unknowns). If we are just to find what the sum is equal to then just 1 is sufficient.

How do I distinguish this? If faced with this question (without the subject line saying hard problems), I would definitely have answered E because we need 5 equations.

I read problem slowly and at least twice, monitoring "red flags" and other special words. It is typical for GMAT to trick us using words like "integer, even, distinct nonzero, consecutive". Here, the question begins: "What is the sum of .....?". By the way, I think the answer is E: sum could be 8 or 9.

matematikconsultant wrote:

But sum of 4 the least from 5 in ours case always < 5 and ........?

Sorry, don't get it. By the way, where did you find such nice problems?
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Walker! Sorry, not sum. Product. If f is largest, then m/f <1, n/f<1, etc and m/f +n/f + p/f +K/f +1 = mnpk -----> mnpk<5. As for problems, I am a trainer on GMAT and I have thought up them

You may add your signature to each post with information that you are a tutor. So, somebody may contact you if he or she is interesting in your services. Of course, if it is appropriate for you. Just a suggestion...
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Walker! Sorry, not sum. Product. If f is largest, then m/f <1, n/f<1, etc and m/f +n/f + p/f +K/f +1 = mnpk -----> mnpk<5. As for problems, I am a trainer on GMAT and I have thought up them

ok. Then, let me ask you the question regarding the 3rd problem. What is the sum could be thought to understand how we can express the sum and not trying to find the actual integers.
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Very simply,If f is largest, then m/f <1, n/f<1, etc and m/f +n/f + p/f +K/f +1 = mnpk -----> mnpk<5 or in other words, mnpk = 1,or 2,or 3,or 4 ------>It is only 1,1,2,2 and 2 or 1,1,1,2 and 5

It is the second impotant condition. 2t/3=L/3y +L/2z L/t=2x -------> 1/3x = 1/3y +1/2z, if y<x then the decision is absent

The decision cannot be absent because "A car traveled from town A to town B...". In other words, a car did travel, so solution exists. We cannot forget real contest behind formulas.
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z cannot be arbitrary because of initial information. z influences on time, and time influences on x. In other words, your example again doesn't fit the information. If you want to give an example, check it for fit the initial conditions and I'm pretty sure you will get av=2x.
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